我有一个数据框,如:
investing.com ft bloomberg
19 API Weekly Distillates Stocks NaN NaN
20 API Weekly Gasoline Stock NaN NaN
21 NaN Advance Goods Trade Balance Advance Goods Trade Balance
22 NaN NaN Advance Retail Sales
23 All Car Sales NaN NaN
24 All Truck Sales NaN NaN
25 Average Hourly Earnings MoM Average Hourly Earnings MoM Average Hourly Earnings MoM
26 NaN NaN Average Hourly Earnings YoY
我想添加一个列,其中包含所有不是NaN的值的计数。
我试过了:
df['count of not NaN'] = df.apply(lambda x:(x[['investing.com','ft','bloomberg']] != 'NaN').count(), axis=1)
但它不起作用。谁知道为什么/可以帮助我正确的配方? (我知道这个问题的某些风格已经发布,但它们无法真正帮助我取得成功......) 谢谢!
答案 0 :(得分:3)
count方法就是这样做的。使用轴= 1来添加列。
df.count(axis=1)