Question

我搜索了如何将用户提供的信息插入到数据库中我在这个论坛上找到了很多方法，但是他们没有工作。你可以给一门课程或者tutoriel怎么做？

感谢您的帮助

PS：我找到的方法 Methode 1：

printf("\nEnter NameID of broker whose priority has to be changed and the new priority");
                 scanf("%s%d",nameID,&priority);
                 sql = " UPDATE BROKERLIST set PRIORITY = '"+priority+"' where NAMEID = '"+nameID+"'; ";
                 rc = sqlite3_exec(db, sql, callback, 0, &zErrMsg);
                 if( rc != SQLITE_OK ){
                        fprintf(stderr, "SQL error: %s\n", zErrMsg);
                        sqlite3_free(zErrMsg);

Methode 2：

char sql[] =
            "INSERT INTO STUDENTS VALUES(?,?,?,?,?,?,?,?,?,?,?,?,?)";
    sqlite3_stmt *stmt = NULL;
    int retval = sqlite3_prepare_v2(handle, sql, -1, &stmt, NULL);
    if (retval != SQLITE_OK) {
        printf("Error while creating insert statement. '%s'",
                sqlite3_errmsg(handle));
        return;
    }
    sqlite3_bind_null(stmt, 1);
    sqlite3_bind_text(stmt, 2, name, -1, SQLITE_STATIC);
    sqlite3_bind_text(stmt, 3, surname, -1, SQLITE_STATIC);
    sqlite3_bind_int(stmt, 4, street_no);
    sqlite3_bind_text(stmt, 5, street_name, -1, SQLITE_STATIC);
    sqlite3_bind_text(stmt, 6, suburb, -1, SQLITE_STATIC);
    sqlite3_bind_int(stmt, 7, postcode);
    sqlite3_bind_int(stmt, 8, student_number);
    sqlite3_bind_text(stmt, 9, dob, -1, SQLITE_STATIC);
    sqlite3_bind_text(stmt, 10, gender, -1, SQLITE_STATIC);
    sqlite3_bind_text(stmt, 11, course, -1, SQLITE_STATIC);
    sqlite3_bind_text(stmt, 12, status, -1, SQLITE_STATIC);
    sqlite3_bind_double(stmt, 13, wam);

Methode 3

string query = "INSERT INTO login (name,username,password) VALUES ('" + username + "','" + name + "','" + password + "');";

如果您可以提供简单的方法，那将是您的好事，因为我没有在学校学习sqlite但是我需要它用于项目使用C管理银行

Answer 1

创建表格

$ sqlite3 test.db
SQLite version 3.6.23.1
Enter ".help" for instructions
Enter SQL statements terminated with a ";"
sqlite> create table t (xyz text);
sqlite> .quit

您可以使用的程序如下。

#include <stdio.h>
#include <sqlite3.h>
#include <stdlib.h>
#include <string.h>
#define CALL_SQLITE(f)                                          \
    {                                                           \
        int i;                                                  \
        i = sqlite3_ ## f;                                      \
        if (i != SQLITE_OK) {                                   \
            fprintf (stderr, "%s failed with status %d: %s\n",  \
                     #f, i, sqlite3_errmsg (db));               \
            exit (1);                                           \
        }                                                       \
    }                                                           \

#define CALL_SQLITE_EXPECT(f,x)                                 \
    {                                                           \
        int i;                                                  \
        i = sqlite3_ ## f;                                      \
        if (i != SQLITE_ ## x) {                                \
            fprintf (stderr, "%s failed with status %d: %s\n",  \
                     #f, i, sqlite3_errmsg (db));               \
            exit (1);                                           \
        }                                                       \
    }

int main ()
{
    sqlite3 * db;
    char * sql;
    sqlite3_stmt * stmt;
    char str[256];
    printf("Please input word to store in sqlite? ");
    fgets(str, sizeof(str), stdin);
    CALL_SQLITE (open ("test.db", & db));
    sql = "INSERT INTO t (xyz) VALUES (?)";
    CALL_SQLITE (prepare_v2 (db, sql, strlen (sql) + 1, & stmt, NULL));
    CALL_SQLITE (bind_text (stmt, 1, str, 6, SQLITE_STATIC));
    CALL_SQLITE_EXPECT (step (stmt), DONE);
    printf ("row id was %d\n", (int) sqlite3_last_insert_rowid (db));
    return 0;
}

使用-lsqlite3

进行编译

   gcc -Wall main.c -lsqlite3

输入单词＆＃34; apple＆＃34;并将其存储在表中如下所示：

$ ./a.out
Please input word to store in sqlite? apple
row id was 4
$ sqlite3 test.db 
SQLite version 3.11.0 2016-02-15 17:29:24
Enter ".help" for usage hints.
sqlite> select * from t;
fruit
fruit
foo

apple

Sqlite和langauge C使用scanf插入

1 个答案: