Question

我有4个表：用户，锻炼，练习和结果。 “用户”发布“练习”的“结果”，其链接到单个“锻炼”。但是当用户发布结果时，由于有多个练习，一个练习的结果可以与唯一的“post_id”链接。我想知道用户根据他们提供了多少“post_ids”来运用的总分钟数，这些“post_ids”可以链接到“Workouts”表，其中“workout_length”列显示每个锻炼持续多少分钟。我还要加上他们的总卡路里......卡路里存储在“练习”表中。这里有一些样本数据，在这种情况下，锻炼（workout_id = 1）有两个练习，锻炼长度为1分钟......每个锻炼每个锻炼消耗1卡路里。

结果：

user_id| workout_id| post_id| exercise_id| number_of_reps|
-------+-----------+--------+------------+---------------+
    123|         1 |       1|          1 |             18|
    123|         1 |       1|          2 |             29|      
    123|         1 |       2|          1 |             15|
    123|         1 |       2|          2 |             30|
    123|         1 |       3|          1 |             20|
    123|         1 |       3|          2 |             28|
-------+-----------+--------+------------+---------------+

锻炼：

workout_id| workout_length|
----------+---------------+
         1|              1|
----------+---------------+

锻炼：

workout_id| exercise_id| calories|
----------+------------+---------+
         1|           1|        1|
         1|           2|        1|  
----------+------------+---------+

用户：

user_id| first_name| last_name|
-------+-----------+----------+
    123|       John|       Doe| 
-------+-----------+----------+

我能够成功生成两个单独的表...一个用于总计总分钟，另一个用于总计卡路里总和;但是，我需要在一个表和GROUP BY用户中获得这些总数。以下是我使用的查询：

总卡路里：

SELECT SUM(calories * reps) as total_cals, user_id, first_name, last_name 
FROM results 
LEFT OUTER JOIN exercises on results.exercise_id = exercises.id        
LEFT OUTER JOIN workouts on results.workout_id = workouts.id 
LEFT OUTER JOIN users on results.user_id = users.id 
GROUP BY user_id, first_name, last_name
ORDER BY total_cals DESC

总分钟数：

SELECT SUM(workout_length) as total_mins, first_name, last_name, user_id
FROM 
(SELECT DISTINCT(results.post_id), users.first_name, users.last_name, workouts.workout_length 
FROM results 
LEFT OUTER JOIN users on results.user_id = users.id 
LEFT OUTER JOIN workouts ON results.workout_id = workouts.id)
GROUP BY first_name, last_name, user_id

这两个查询都可以单独运行，但是当我尝试使用WITH语句将它们组合成一个查询时，SQLite3会抛出一个错误，指出“workout_length列不存在”。我知道要看很多东西......但是有什么想法吗？

WITH minute_table AS (SELECT SUM(workouts.workout_length) as total_mins, user_id 
FROM 
(SELECT DISTINCT(results.post_id), users.id 
FROM results 
LEFT OUTER JOIN users on results.user_id = users.id 
LEFT OUTER JOIN workouts ON results.workout_id = workouts.id) 
GROUP BY user_id), 
cals_table AS 
(SELECT SUM(calories * reps) as total_cals, user_id, first_name, last_name   
FROM results 
LEFT OUTER JOIN exercises ON results.exercise_id = exercises.id 
LEFT OUTER JOIN workouts ON results.workout_id = workouts.id 
LEFT OUTER JOIN users on results.user_id = users.id 
GROUP BY user_id, first_name, last_name) 
SELECT cals_table.first_name, cals_table.last_name, cals_table.total_cals, minute_table.total_mins 
FROM minute_table 
JOIN cals_table ON minute_table.user_id = cals_table.user_id

Answer 1

我想通了......只需要添加＆＃34; workouts.workout_length＆＃34;到第一个SELECT语句。

WITH minute_table AS (SELECT SUM(workout_length) as total_mins, user_id 
FROM 
(SELECT DISTINCT(results.post_id), workouts.workout_length, users.id as user_id
FROM results 
LEFT OUTER JOIN users on results.user_id = users.id 
LEFT OUTER JOIN workouts ON results.workout_id = workouts.id) 
GROUP BY user_id), 
cals_table AS 
(SELECT SUM(calories * reps) as total_cals, user_id, first_name, last_name   
FROM results 
LEFT OUTER JOIN exercises ON results.exercise_id = exercises.id 
LEFT OUTER JOIN workouts ON results.workout_id = workouts.id 
LEFT OUTER JOIN users on results.user_id = users.id 
GROUP BY user_id, first_name, last_name) 
SELECT cals_table.first_name, cals_table.last_name, cals_table.total_cals, minute_table.total_mins 
FROM minute_table 
JOIN cals_table ON minute_table.user_id = cals_table.user_id

加入通过两个WITH语句创建的两个表时的SQL错误 - SQLite3

1 个答案: