jQuery - 获取对此的引用

Question

function Request(params)
{
    // Stuff stuff stuff

    // And then

    $.ajax(
    {
        type: 'GET',
        url: 'someurl',
        success: this.done
    });
}

Request.prototype.done = function()
{
    // "this" in this context will not refer to the Request instance.
    // How to reach it?
}

Answer 1

你可以先捕获“这个”：

function Request(params)
{
    // Stuff stuff stuff

    // And then

    var $this = this;

    $.ajax(
    {
        type: 'GET',
        url: 'someurl',
        success: function() { $this.done(); }
    });
}

Answer 2

显然你可以将“context”参数添加到ajax请求中，如下所示：

$.ajax(
{
    type: 'GET',
    url: 'someurl',
    success: this.done,
    context: this
});

Answer 3

this并不是指同一件事!!!“

Answer 4

尝试以下：

function Request(params)
{
   var that = this;

...

Request.prototype.done = function()
{
   that...