Question

我认为A 1，A 12，A 123，A 1234和B 1，B 12，B 123相同，B 1234其中123表示三位数现在，当我这样做时：

MatchCollection ForA1 = Regex.Matches(inFile, @"\b(A [0-9])\b");
MatchCollection ForA2 = Regex.Matches(inFile, @"\b(A [0-9][0-9])\b");
.... and so on for three and four digits and B; total 8 lines

减少我执行此操作的代码：

MatchCollection ForAB1 = Regex.Matches(inFile, @"\b(A [0-9]|B [0-9])\b");
MatchCollection ForAB2 = Regex.Matches(inFile, @"\b(A [0-9][0-9]|B [0-9][0-9])\b");
.... and so on for three and four digits; total 4 lines

现在我想这样做：

MatchCollection ForAB1234 = Regex.Matches(inFile, @"\b(A [0-9]|B [0-9]...
|A [0-9][0-9]|B [0-9][0-9] and so on for three and four digits )\b"); total 1 line

在比赛后的这个时间我这样做：

foreach (Match m in ForAB1)
   {
     //many calculations on the basis of index and length etc
     }

我想要的是什么：

foreach (Match m in ForAB1)
   {
     if(Match is 'A [0-9]')
     {//many calculations on the basis of index and length etc}
     else...
   }

有没有其他简单的东西，以便我不需要仅仅因为不同的位数而重复代码？我正在寻找我用过的所有不同的比赛。

编辑：真正的问题是我不想m.len然后检查它是A还是B，因为实际上我有超过30个这样的表达

Answer 1

要确保只检查A 1类型而不是A 11类型，您需要使用类似

的内容

foreach (Match m in ForAB1)
 {
     if (Regex.IsMatch(m.Value, @"^A [0-9]$"))
     {//many calculations on the basis of index and length etc}
     else if (Regex.IsMatch(m.Value, @"^A [0-9]{2}$"))
     {//many calculations on the basis of index and length etc}
     else...
 }

从MatchCollection C＃获取完整的单词

1 个答案: