Question

我一直在尝试使用Intent在两个活动之间传递多个（不同类型的）值。到目前为止，我已尝试过这两种方法：

Intent intent = new Intent(context, Receiver.class);
Bundle bundle = new Bundle();
bundle.putInt("key1", v1);
bundle.putString("key2", v2);
bundle.putString("key3", v3);
bundle.putInt("key4", v4);
intent.putExtras(bundle);

和

Intent intent = new Intent(context, Receiver.class);
intent.putInt("key1", v1);
intent.putString("key2", v2);
intent.putString("key3", v3);
intent.putInt("key4", v4);

然而，在两种情况下似乎只保留key1的值（当使用Bundle时，它显然只包含1个键）。我错过了什么？

修改：这是我在Receiver中检索值的方法：

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_video);

    Intent intent = getIntent();
    Bundle bundle = intent.getExtras();
    v1 = bundle.getInt("key1", DEFAULT1);
    v2 = bundle.getString("key2", "DEFAULT2");
    v3 = bundle.getString("key3", "DEFAULT3");
    v4 = bundle.getInt("key4", DEFAULT4);

    // ...
}

可替换地：

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_video);

    Intent intent = getIntent();
    v1 = intent.getIntExtra("key1", DEFAULT1);
    v2 = intent.getStringExtra("key2");
    v3 = intent.getStringExtra("key3");
    v4 = intent.getIntExtra("key4", DEFAULT2);

    // ...
}

当我打印出v1，v2，v3和v4的值时，v1是唯一一个非空/ {非默认值（我最初放在key1中的值 - 实际上，我最初放入Intent的所有值都是非默认值。）

编辑2：

我尝试使用getBundleExtra()，如此：

intent.putExtra("bundle", bundle);

然后在Receiver：

Bundle bundle = intent.getBundleExtra("bundle");

但是，bundle为空。

编辑3：

更改从Intent放入/检索值的顺序似乎不会影响任何内容。也没有指定Bundle的容量。如果有帮助，则此Intent用于PendingIntent。

Answer 1

您可以在不使用Bundle的情况下简单地传递和接收Intent Extras。

<强> SenderClass.java

>>> Creating reader: 0
>>> Creating reader: 1
>>> Creating reader: 2
>>> Creating writer: 0
INFO::About to access entry mutex for reader with ID:  1, with queue length  1.
INFO::About to exit entry mutex for reader with ID:  1, with queue length  0.
[READER (ID:  1):] Readers in queue:  0, read:  0
>>> Creating writer: 2
>>> Creating writer: 1
[WRITER (ID:  0):] Readers in queue:  0, wrote:  0
[WRITER (ID:  0):] Readers in queue:  0, wrote:  1
!!! Destroying writer: 0
[WRITER (ID:  1):] Readers in queue:  0, wrote:  5
[WRITER (ID:  1):] Readers in queue:  0, wrote:  6
!!! Destroying writer: 1
[WRITER (ID:  2):] Readers in queue:  0, wrote: 10
[WRITER (ID:  2):] Readers in queue:  0, wrote: 11
!!! Destroying writer: 2
INFO::About to access entry mutex for reader with ID:  1, with queue length  1.
INFO::About to exit entry mutex for reader with ID:  1, with queue length  0.
[READER (ID:  1):] Readers in queue:  0, read: 11
!!! Destroying reader: 1
INFO::About to access entry mutex for reader with ID:  2, with queue length  1.
INFO::About to exit entry mutex for reader with ID:  2, with queue length  0.
[READER (ID:  2):] Readers in queue:  0, read: 11
INFO::About to access entry mutex for reader with ID:  0, with queue length  1.
INFO::About to exit entry mutex for reader with ID:  0, with queue length  0.
[READER (ID:  0):] Readers in queue:  0, read: 11
INFO::About to access entry mutex for reader with ID:  0, with queue length  1.
INFO::About to exit entry mutex for reader with ID:  0, with queue length  0.
[READER (ID:  0):] Readers in queue:  0, read: 11
!!! Destroying reader: 0
INFO::About to access entry mutex for reader with ID:  2, with queue length  1.

ERROR::Before entry mutex!


ERROR::During entry mutex!

INFO::About to exit entry mutex for reader with ID:  2, with queue length -1.
[READER (ID:  2):] Readers in queue: -1, read: 11
!!! Destroying reader: 2

<强> Receiver.java

Intent intent = new Intent(getApplicationContext(), Receiver.class);
intent.putExtra("key1", key1);
intent.putExtra("key2", key2);
intent.putExtra("key3", key3);
startActivity(intent)

Answer 2

原来我忽略了一些非常简单的东西 - 我的意图在PendingIntent中被用来触发接收器然后启动服务，但我忘了将Bundle从原来的Intent正确地转移到（新的，不同的）Intent最终由第二个活动（由服务启动）收到。问题已经解决了。

Android：无法将多个值放入Intent / Bundle

2 个答案: