当我选择一些文本然后运行下面的代码时,我可以在所选文本之前和之后替换两个字符,但如果我在脚注中选择文本,则此代码不起作用..如何使其工作还有?
var myStory = app.selection[0].parentStory;
var myIndex = app.selection[0].index;
var myInS = app.selection[0].insertionPoints[0].index;
var toplam = app.selection[0].characters.length
var toplama = app.selection[0].insertionPoints.length;
var myText1 = myStory.characters[myIndex-1];
var myText2 = myStory.characters[myIndex+toplam+0];
myText1.contents = "\uFD3F";
myText2.contents = "\uFD3E";
答案 0 :(得分:1)
直接使用:
app.selection[0].insertionPoints[-1].contents = "\uFD3E";
app.selection[0].insertionPoints[0].contents = "\uFD3F";
如果要更换:
var
myParent = app.selection[0].parent,
char1 = myParent.characters[app.selection[0].characters[0].index - 1],
char2 = myParent.characters[app.selection[0].characters[-1].index + 1];
char2.contents = "\uFD3E";
char1.contents = "\uFD3F";
它假设选择介于任何字符之间(并且不仅仅是插入点...)
亚雷克