当我运行此代码时，我得到A heap has been corrupted
这是我的代码：
#include "opencv2\opencv.hpp"
using namespace cv;
//This program with take a Video, separate it into it's blue, green and red channels and display them.
//It will then convert the video into HSV and do the same with it's hue, saturation, and value channels
int main() {
Mat src, hsv, hls;
Mat blue, green, red, hue1, saturation1, value, hue2, light, saturation2;
bool quit = false;
VideoCapture videoCapture(0);
//create window
cv::namedWindow("SplitImage");
while (!quit) {
//read in image
videoCapture >> src;
//convert image to hsv and hsl
cvtColor(src, hsv, CV_BGR2HSV);
cvtColor(src, hls, CV_BGR2HLS);
//copy src to blue, green, and red matrices
src.copyTo(blue);
src.copyTo(green);
src.copyTo(red);
//copy hsv to hue1, saturation1, and value matrices
hsv.copyTo(hue1);
hsv.copyTo(saturation1);
hsv.copyTo(value);
//copy hls to hue2, light and saturation2
hls.copyTo(hue2);
hls.copyTo(light);
hls.copyTo(saturation2);
//resize windows
Size size = Size(200, 200);
resize(src, src, size);
resize(hsv, hsv, size);
resize(hls, hls, size);
resize(blue, blue, size);
resize(green, green, size);
resize(red, red, size);
resize(hue1, hue1, size);
resize(saturation1, saturation1, size);
resize(value, value, size);
resize(hue2, hue2, size);
resize(light, light, size);
resize(saturation2, saturation2, size);
//get number of rows, columns, and channnels
int nRows = size.height;
int channels = src.channels();
int nCols = size.width * channels;
//put matrices in array
Mat matrices[9] = { blue, green, red, hue1, saturation1, value, hue2, light, saturation2 };
//declare the pointers that will access the matrices' data
uchar * p[9];
//for readability I will access the pointer with
//these constants instead of numbers
const int blueIdx = 0, greenIdx = 1, redIdx = 2,
hue1Idx = 3, sat1Idx = 4, valueIdx = 5,
hue2Idx = 6, lightIdx = 7, sat2Idx = 8;
//make blue matrix blue, green matrix green and red matrix red
//and make hue matrix only have hue, saturation matrix only have saturation, and value matrix only have value
for (int row = 0; row < nRows; row++) {
//each element in p points to the first element in the row of each matrix
//for (int i = 0; i < 9; i++) {
// p[i] = matrices[i].ptr<uchar>(row);
//}
for (int col = 0; col < nCols; col += channels) {
//std::cout <<"separating at pixel coordinate"<< "(" << col << ", " << row<<")" << std::endl;
// remember that pointer + 0 is the blue pixel, pointer + 1 is the green
// pixel and pointer + 2 is the red pixel
//turn pixel in blue matrix blue
/*p[blueIdx][col + 1] = 0;
p[blueIdx][col + 2] = 0;*/
blue.data[row*nCols + col*channels + 1] = 0;
blue.data[row*nCols + col*channels + 2] = 0;
//turn pixel in green matric green
//p[greenIdx][col + 0] = 0;
//p[greenIdx][col + 2] = 0;
green.data[row*nCols + col*channels + 0] = 0;
green.data[row*nCols + col*channels + 2] = 0;
//turn pixel in red matrix red
//p[redIdx][col + 0] = 0;
//p[redIdx][col + 1] = 0;
red.data[row*nCols + col*channels + 0] = 0;
red.data[row*nCols + col*channels + 1] = 0;
// remember that pointer + 0 is the hue pixel, pointer + 1 is the saturation
// pixel and pointer + 2 is the value pixel
//turn pixel in hue matrix hue
/*p[hue1Idx][col + 1] = 0;
p[hue1Idx][col + 2] = 0;*/
hue1.data[row*nCols + col*channels + 1] = 0;
hue1.data[row*nCols + col*channels + 2] = 0;
//turn pixel in saturation matric saturation
/*p[sat1Idx][col + 0] = 0;
p[sat1Idx][col + 2] = 0;*/
saturation1.data[row*nCols + col*channels + 0] = 0;
saturation1.data[row*nCols + col*channels + 2] = 0;
//turn pixel in value matrix value
/*p[valueIdx][col + 0] = 0;
p[valueIdx][col + 1] = 0;*/
value.data[row*nCols + col*channels + 0] = 0;
value.data[row*nCols + col*channels + 1] = 0;
//turn pixel in hue matrix hue
/*p[hue2Idx][col + 1] = 0;
p[hue2Idx][col + 2] = 0;*/
hue2.data[row*nCols + col*channels + 1] = 0;
hue2.data[row*nCols + col*channels + 2] = 0;
//turn pixel in saturation matric saturation
/*p[lightIdx][col + 0] = 0;
p[lightIdx][col + 2] = 0;*/
light.data[row*nCols + col*channels + 0] = 0;
light.data[row*nCols + col*channels + 2] = 0;
//turn pixel in light matrix value
/*p[sat2Idx][col + 0] = 0;
p[sat2Idx][col + 1] = 0;*/
saturation2.data[row*nCols + col*channels + 0] = 0;
saturation2.data[row*nCols + col*channels + 1] = 0;
}
}
//put indentifying text on each matrix
Point textPosition = Point(5, 10);
putText(src, "src", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);//THIS IS LINE 131 WHERE THE ERROR OCCURS
putText(hsv, "hsv", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(hls, "hls", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(blue, "blue", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(green, "green", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(red, "red", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(hue1, "hue1", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(saturation1, "saturation", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(value, "value", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(hue2, "hue", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(light, "light", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
putText(saturation2, "saturation", textPosition, FONT_HERSHEY_PLAIN, 1, Scalar(255, 255, 255), 2);
//concatenate images
Mat topRow, middleRow, bottomRow, finalImage;
std::vector<Mat> top = { src, blue, green, red };
std::vector<Mat> middle = { hsv, hue1, saturation1, value };
std::vector<Mat> bottom = { hls, hue2, light, saturation2 };
hconcat(top, topRow);
hconcat(middle, middleRow);
hconcat(bottom, bottomRow);
std::vector<Mat> allRows = { topRow, middleRow, bottomRow };
vconcat(allRows, finalImage);
//show matrices in window
cv::imshow("SplitVideo", finalImage);
if(cv::waitKey(30) == 'q') quit = true;
}
}
代码从网络摄像头获取视频a显示红色绿色和蓝色通道，然后将其转换为HSV并显示色调饱和度和值通道，然后将视频转换为HLS并显示色调光和饱和通道。这些论文在一个窗口中并排显示
正如您在代码中看到的那样，我通过使用<Mat object>.ptr<uchar>(row)来获取指向每一行的指针，而不是使用<Mat object>.data来获取指向所有行的指针，我已经注释掉了另一种执行相同操作的方法。的数据。当我使用注释掉的方法时，代码运行没有错误。我可以使用它，但我想知道为什么<Mat object>.data方法不起作用。
我确信<Mat object>.data行是造成错误的原因，即使这些行没有发生错误，因为我在另一个也使用了该错误的应用程序中遇到了同样的错误相同的<Mat object>.data代码，我得到相同的错误。 （我发布的内容是两个应用程序中的简单内容）
答案 0 :(得分：2)
你不应该乘以col *频道。您已经通过循环中的多个通道推进它。所以你应该写例如。
blue.data[row*nCols + col + 1] = 0;
等