Question

说我有这个：

interface Point {
    x: number;
    y: number;
}

interface Line {
    vertix1: Point;
    vertix2: Point;
}

let v1: Point = { x: 1, y: 2 };
let v2: Point = { x: 1, y: 2 };
let line: Line = {vertix1: v1, vertix2: v2};

如何在不定义line和v1的情况下直接定义v2？我试过，显然，这不起作用：

let line1: Line = {
    vertix1: Point = { x: 1, y: 2 },
    vertix2: Point = { x: 1, y: 2 },
}

Answer 1

这只是：

let line1: Line = {
    vertix1: { x: 1, y: 2 },
    vertix2: { x: 1, y: 2 },
}

可以很容易地跳过

类。

Answer 2

使用实现接口的类可能会更好。

interface IPoint {
    x: number;
    y: number;
}

interface ILine {
    vertix1: Point;
    vertix2: Point;
}

class Point implements IPoint {
  x: int;
  y: int;

  constructor(x: int, y: int) {
    this.x = x;
    this.y = y;
  }
}

class Line implments ILine {
  vertix1: Point;
  vertix2: Point;

  constructor(vertix1: Point, vertix2: Point) {
    this.vertix1 = vertix1;
    this.vertix2 = vertix2;
  }
}
let v1: Point = new Point(1,2);
let v2: Point = new Point(1,2);
let line: Line = new Line(v1,v2);

您还可以在构造函数中创建点。不确定这是否能回答你的问题，但希望它有所帮助。

let line: Line = new Line(new Point(1,2), new Point(1,2))

如何在对象中使用接口

2 个答案: