Question

我正在运行输出到控制台的线程。

要知道何时输出到控制台我使用监听器进行变量更改。

但是那个听众在循环中燃烧了很多处理能力。是否有更有效的方式来倾听变化？

以下是代码：

def output_console_item(message, sound=None, over_ride_lock=False):
    log = StandardLogger(logger_name='output_console_item')
    # lock to serialize console output
    lock = threading.Lock()

    def print_msg(message):

        # Wait until console lock is released.
        if over_ride_lock is False:
            while True:
                if CONSOLE_CH.CONSOLE_LOCK is False:
                    break
                # time.sleep(0.10)

        # Make sure the whole print completes or threads can mix up output in one line.
        with lock:
            print(message)

    return

thread = Thread(target=print_msg, args=(message,))
thread.start()
thread.join()

if sound:
    thread = Thread(target=play_sound, args=(sound,))
    thread.start()
    thread.join()

Answer 1

你不需要另一个线程为你打印东西，

您可以创建安全的打印，例如

lock = threading.Lock()
def safe_print(message):
    with lock:
        print message

并在所有线程中使用它

甚至更好地使用已经线程安全的python模块日志记录

编辑：

您可以将CONSOLE_LOCK更改为真正的锁定并使用类似这样的东西

def print_msg(message):

    # Wait until console lock is released.
    if over_ride_lock is False:
        with CONSOLE_LOCK:
            pass


    with lock:
        print(message)

而不是做CONSOLE_LOCK = True做CONSOLE_LOCK.acquire而不是做CONSOLE_LOCK = False做CONSOLE_LOCK.release（）

Processer高效的方式来监听线程中的变量

1 个答案: