如何使用Python的re.sub来匹配和替换组零次或多次？

Question

import re
host = 'www.example.com'
urls = [
'auth_redirect_url = aaa.bbb.ccc.com/auth-web',
'auth_redirect_url = aaa.bbb.ccc.com'
]    
for url in urls:
    print re.sub(r'(^auth_redirect_url\s*=\s*)(.*)(/.*)', r'\g<1>{}\g<3>'.format(host), url)

我想更换主机名＆＃39; aaa.bbb.ccc.com＆＃39;到＆＃39; www.example.com＆＃39;，但正则表达式不起作用，因为url中的路径可能不存在。有没有办法匹配一个组0次或更多次？或者如何处理这个问题？

Answer 1

此方法可以帮助您

text_filtered = re.sub(r'<p ([^>]*)>', '<p>', text_filtered) # remove the other field from p tag

Answer 2

您的第二组可以捕获除/以外的所有内容：

import re

host = 'www.example.com'
urls = [
    'auth_redirect_url = aaa.bbb.ccc.com/auth-web',
    'auth_redirect_url = aaa.bbb.ccc.com'
]

for url in urls:
    print re.sub(r'(^auth_redirect_url\s*=\s*)([^/]*)(.*)',
                 r'\g<1>{}\g<3>'.format(host), url)

输出：

auth_redirect_url = www.example.com/auth-web
auth_redirect_url = www.example.com