Question

我希望有人可以提供实际的例子

我从各种帖子中得到了这么多，但我一直得到不好的请求。

基本上我想要实现的是使用AppToken键登录，然后从Response中检索SessionToken。这是他们从API文档中发布的信息

请求（JSON）
POST / login / application
Content-Type：application / json
{＆＃34;名称＆＃34;：＆＃34;万分之一＆＃34 ;, ＆＃34;键＆＃34;：＆＃34; longstringasyourpasscodegeneratedfromtheapplication＆＃34;}

响应如下（使用简单REST客户端时）

<Login xmlns="http://schemas.datacontract.org/2004/07/Tamigo.Services.Entities" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"><DefaultCompanyId i:nil="true"/><DefaultCompanyName i:nil="true"/><DefaultDepartmentId i:nil="true"/><DefaultDepartmentName/><Email/><EmployeeId i:nil="true"/><ImageUrl i:nil="true"/><MenuId>0</MenuId><Name i:nil="true"/><Password/><Role>Application</Role><SessionToken>e1f35353-08f7-4213-a6b9-251313b36701</SessionToken></Login>

从那个响应中我需要以某种方式获得＆＃34; SessionToken＆＃34;到下一个GET请求中使用的变量。

这是我到目前为止编写的代码，这是我可以从其他类似问题中找到的代码片段（当然，这些代码并不适合我显然完全独特/从未见过的类型请求）：

using System;
using System.Xml;
using System.Net;
using System.Text;
using System.IO;

namespace RESTServicesXMLParseExample
{
    class Program
    {
        static void Main(string[] args)

        {
            try
            {
                var request =
                    (HttpWebRequest)WebRequest.Create("https://api.tamigo.com/login/application");

                var postData = "Name=test";
                postData += "&Key=y3LIZ5u5yR9A7a98ypBdygQyIBrqQwZdfdfZKmgtErQ=";
                var data = Encoding.ASCII.GetBytes(postData);

                request.Method = "POST";


                request.ContentType = "application/x-www-form-urlencoded";
                request.ContentLength = data.Length;

                using (var stream = request.GetRequestStream())
                {
                    stream.Write(data, 0, data.Length);
                }

                var response = (HttpWebResponse)request.GetResponse();

                var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();

                //Create the REST Services 'Find by Query' request

                XmlDocument locationsResponse = MakeRequest(responseString);
                ProcessResponse(locationsResponse);
            }
            catch (Exception e)
            {
                Console.WriteLine(e.Message);
                Console.Read();
            }
        }


        //Submit the HTTP Request and return the XML response
        public static XmlDocument MakeRequest(string requestUrl)
        {
            try
            {
                HttpWebRequest request = WebRequest.Create(requestUrl) as HttpWebRequest;
                HttpWebResponse response = request.GetResponse() as HttpWebResponse;

                XmlDocument xmlDoc = new XmlDocument();
                xmlDoc.Load(response.GetResponseStream());
                return (xmlDoc);

            }
            catch (Exception e)
            {
                Console.WriteLine(e.Message);

                Console.Read();
                return null;
            }
        }

        static public void ProcessResponse(XmlDocument locationsResponse)
        {
            //Create namespace manager
            XmlNamespaceManager nsmgr = new XmlNamespaceManager(locationsResponse.NameTable);
            nsmgr.AddNamespace("rest", "http://schemas.datacontract.org/2004/07/Tamigo.Services.Entities");


            XmlNodeList formattedAddressElements = locationsResponse.SelectNodes("//rest:SessionToken", nsmgr);
            Console.WriteLine("SessionToken");
            foreach (XmlNode SessionToken in formattedAddressElements)
            {
                Console.WriteLine(SessionToken.InnerText);
            }
            Console.WriteLine();

            Console.WriteLine("Press any key to exit");
            Console.ReadKey();
        }
    }
}

Answer 1

如果您的API文档告诉您发送应用程序/ json有效负载，那么您最好不要忽略它，因为内容类型application/x-www-form-urlencoded实际上是不同的。

通过以下更改，我获得了401 Unauthorized，因为我希望密钥和/或名称无效。所以我解决了Bad Request的问题。

var request = (HttpWebRequest)WebRequest.Create("https://api.tamigo.com/login/application");

request.Method = "POST";
request.ContentType = "application/json";

// create the serializer for the Login class
var ser = new DataContractJsonSerializer(typeof(Login));
// set our login values
var login = new Login{ Name="test", Key ="y3LIZ5u5yR9A7a98ypBdygQyIBrqQwZdfdfZKmgtErQ=" };

// serialize the Login instance directly to the request stream
ser.WriteObject(request.GetRequestStream(), login);

// handle response
var response = (HttpWebResponse)request.GetResponse();

var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();

这是我使用的小助手类，因此DataContractJsonSerializer可以完成它的工作：

public class Login
{
   public string Name;
   public string Key;
}

使用REQUEST POST数据以获取SessionToken

1 个答案: