我使用$ http.get api从数据库中检索内容,并使用ng-repeat
显示每条记录。对于每个记录,我有一个like and comment button.
点击按钮,我使用$ http.post插入记录,我必须change the name of button to "Liked"
。问题是 - 点击任何一个记录按钮,所有其他记录,如按钮名称更改为喜欢,包括点击按钮。
<div ng-repeat="dat in details | filter : { product_name : textname} as results">
<p style="color:#4C97C8;" class="lead"><strong>{{dat.summary}}</strong></p>
<ul>
<li><b>Product:</b><span> {{dat.product_name}}</span></li>
<li><b>Product Manager:</b><span> {{dat.first_name}} {{dat.last_name}}</span></li>
<li><b>Description:</b><span> {{dat.description}}</span></li>
</ul>
<button style="background-color:#4C97C8;color:white;height:30px" class="btn buttonlike" ng-click="likebtn(dat.id,loginname)"><span class="glyphicon glyphicon-hand-right"></span><strong> {{ likebtnname }}</strong></button>
<button style="background-color:#4C97C8;color:white;height:30px" class="btn" ng-disabled="comment" ng-click="comment=true"><span class="glyphicon glyphicon-comment"></span><strong> Comment</strong></button>
<div class="input-group " ng-show="comment">
<input type="text" id="commentarea" name="commentarea" class="form-control" placeholder="comment" aria-describedby="basic-addon2" ng-model="takecomment">
<span class="input-group-addon" id="basic-addon2" ng-click="takecomment=mycomment(dat.id,takecomment)"><span class="glyphicon glyphicon-send"></span></span>
</div>
</div>
脚本/控制器中的likebtn()方法是
$scope.likebtnname="Like";
$scope.likebtn = function(idvalue,namevalue) {
var likereque = {
method: 'POST',
url: "https://url/Likes",
headers: {
"Content-Type": "application/json"
},
data: {
"platform": {
"record": { "idea_record": idvalue,
"liker": $scope.loginname
}
}
}
}
$http(likereque).then(function(){
alert("Liked Successfully");
$scope.likebtnname="Liked"; },
function(){alert("try again");});
}
如何更改单击按钮的名称?
答案 0 :(得分:1)
<强> HTML:强>
<button style="background-color:#4C97C8;color:white;height:30px" class="btn buttonlike" ng-click="$parent.likebtn(dat.id,loginname, dat)"><span class="glyphicon glyphicon-hand-right"></span><strong> {{ dat.likebtnname||'Like' }}</strong></button>
<强>使用Javascript:强>
$scope.likebtn = function(idvalue,namevalue,dat) {
var likereque = {
method: 'POST',
url: "https://url/Likes",
headers: {
"Content-Type": "application/json"
},
data: {
"platform": {
"record": { "idea_record": idvalue,
"liker": $scope.loginname
}
}
}
}
$http(likereque).then(function(){
alert("Liked Successfully");
dat.likebtnname="Liked"; },
function(){alert("try again");});
}
答案 1 :(得分:0)
现在你有一个变量$scope.likebtnname
,所以当你改变它时,它会改变所有。
您可以使用track by $index
进行ng-repeat,然后使用数组$scope.likebtnname[$index]
并仅更改通过$index
所需的数组。
答案 2 :(得分:0)
由于它们都具有相同的名称,因此常见,因此一个解决方案可以动态更改名称。 $ index的第一首曲目
div ng-repeat="dat in details track by $index| filter : { product_name : textname} as results">
然后在您的按钮中添加ID
<button style="background-color:#4C97C8; ng-model="$index"
然后在你的函数中传递那个id
ng-click="likebtn(dat.id,loginname,$index)"
然后使用id update dom
$scope[id]="Liked";
答案 3 :(得分:0)
from pathlib import Path
path = "/Users/Desktop/test/"
p = Path(path)
for file in p.iterdir():
if not file.is_file():
continue
print(file)
print(file.read_text())