Question

例如，

我有这样的输出： -

ID
---
AB1
AB2
AB3
AB4
BD6

如果我使用MAX(ID)，我会得到'BD6'但我想查看MAX价值模式AB

我怎么能得到它？

Answer 1

只需过滤带有ID的数据字段，然后使用Max（）：

编辑：如果ID包含的数字超过1位数：

SELECT TOP 1 *
FROM
    [Table] AS A
WHERE
    RIGHT(ID, LEN(ID) - 2) = (SELECT 
               MAX(Cast(RIGHT(ID, LEN(ID) - 2) AS Int)) FROM [Table] WHERE ID LIKE 'AB%')
    AND
    ID LIKE 'AB%'

Answer 2

试试这个。它将显示每个String的所有最大ID。

         select CONCAT(ID,id1) as ID   from
         (
         select left(id, patindex('%[^0-9]%', id) + 1) ID , max(cast(substring(id, PatIndex('%[0-9]%', id),len(id)) as numeric)) id1
         from #Table
         group by left(id, patindex('%[^0-9]%', id) + 1)
         )a

对于特定ID值，例如＆＃39; AB＆＃39;将值放入where子句。

         select CONCAT(ID,id1) as ID  from
         (
         select left(id, patindex('%[^0-9]%', id) + 1) ID , max(cast(substring(id, PatIndex('%[0-9]%', id),len(id)) as numeric)) id1
         from #Table
         group by left(id, patindex('%[^0-9]%', id) + 1)
         )a
         where ID like '%ab%'

OutPut：

outpur for AB111

此处还可以查看demo。

Answer 3

试试这个：

SELECT      'AB' + CONVERT(NVARCHAR(10),MAX(CONVERT(INT, Nums.Numbers)))
FROM        (SELECT     Substring(ID, 3, 10) as Numbers
            FROM        #Tab tab
            WHERE       tab.ID LIKE 'AB%') as Nums

你可以在这里看到这个=＆gt; http://rextester.com/MAHKWE99983

希望这有帮助!!!

Answer 4

试试吧，

DECLARE @TABLE TABLE(ID VARCHAR(MAX)) 

INSERT INTO @TABLE (ID)
VALUES('AB1'),('AB2'),('AB3'),('AB4'),('AB11'),('AB111'),('XY112')

DECLARE @Prefix VARCHAR (10) = 'AB' 

SELECT  @Prefix + CAST(MAX(CAST(SUBSTRING(ID, (LEN(@Prefix) + 1),
(LEN(ID) - 2)) AS INT)) AS VARCHAR) AS ID FROM @TABLE WHERE ID LIKE
@Prefix +'%'

Answer 5

您可以通过此查询获取。

create table temp
(
id varchar(10)
);
insert into temp values
('AB111'),
('AB1'),
('AB2'),
('AB3'),
('AB4'),
('BD6'),
('AB111')
;


declare @Pattern varchar(5)
set @Pattern='AB'
select distinct(Id) from temp where Id = @Pattern+convert(varchar(10),(
select MAX(Id) as Maximum from (
SELECT convert(integer,REPLACE( Id,@Pattern,'')) as Id FROM temp
where id like 'AB%'
)as test ))

Answer 6

with tmp as (
select 'AB1' id union all
select 'AB2' id union all
select 'AB3' id union all
select 'AB4' id union all
select 'AB111' id union all
select 'BD6' id
)
select top 1 *  from tmp f1
where  f1.ID LIKE 'AB%' and cast(SUBSTRING(f1.ID, 3, LEN(ID) -2) as integer) in 
 (
select max(cast(SUBSTRING(f2.ID, 3, LEN(ID) -2) as integer)) from tmp f2
WHERE f2.ID LIKE 'AB%' 
)

Answer 7

SELECT MAX(ID) FROM #Tbl 
GROUP BY LEFT(col_name,2)

如何使用模式检查MAX值

7 个答案: