Question

如果我的某个按钮被选中并且鼠标滚轮被激活，那么它的大小应该根据鼠标滚轮动作而改变。如果鼠标滚轮上升，我的按钮大小应该增加2。如果鼠标滚轮向下移动，我按钮的大小应减少2。

我正在尝试这样的事情：

var a = '[{"SNO":1,"SNUMBER":"827","STARTDATE":"11/12/2016","STARTTIME":"03:06:50 PM","ITEMNAME":"KBand","ITEMCODE":"KB2541","ITEMSKUNAME":"Band","ITEMSKUCODE":"BT102","SALESRATE":100.0,"PURCHASERATE":5.0,"DOE":"~","STOCKQTY":2.0,"PHYSICALQTY":1.0}]'

var output = JSON.parse(a)

console.log(output[0].PHYSICALQTY)

不幸的是我的代码不起作用。

Answer 1

现在已经解决了：

    private void Form1_Load(object sender, EventArgs e)
    {
        foreach (Control c in this.Controls)
        {
            btn = c as Button;
            {
                if (btn == null)
                    continue;

               c.MouseWheel += c_MouseWheel;


            }
        }
    }
    private void c_MouseWheel(object sender, MouseEventArgs e)
    {
        ss = sender as Button;
        TabControl tabControl = sender as TabControl;
        int y = ss.Size.Width;
        int x = ss.Size.Height;

            if (e.Delta < 0)
            {

                ss.Size = new Size(y+2, x+2);
            }
            else
            {

                ss.Size = new Size(y-2, x-2);
            }

使用鼠标滚轮上/下事件更改鼠标大小

1 个答案: