Question

我有两张表tbl_tools和tbl_tool_use。 tbl_tool_use表看起来像这样

id  user_id     type    tool_id     quantity    start_date  end_date
30  27         engineer     5          2        2016-12-22  
31  gdf         team        8          2        2016-12-22  
32  26         engineer     7          2        2016-12-22  
33  26         engineer     7          2        2016-12-23  
34  hamsu       team        6          2        2016-12-22  
35  27        engineer      7,5        2,2      2016-12-22

tbl_tools表看起来像这样

id  name            quantity    available   type        
5   cutting player     5          5        engineer     
6   reflectors         2          2        team     
7   spanner            8          8        engineer     
8   tester             4          4        team

我希望我的结果是这样的：

id  user_id     type       tool_id             quantity     start_date  end_date
30  27         engineer  cutting player            2        2016-12-22  
31  gdf         team     tester                    2        2016-12-22  
32  26         engineer  spanner                   2        2016-12-22  
33  26         engineer  spanner                   2        2016-12-23  
34  hamsu       team     reflectors                2        2016-12-22  
35  27        engineer   cutting player,spanner    2,2      2016-12-22

但是我得到这样的

 id user_id     type       tool_id             quantity     start_date  end_date
30  27         engineer  cutting player            2        2016-12-22  
31  gdf         team     tester                    2        2016-12-22  
32  26         engineer  spanner                   2        2016-12-22  
33  26         engineer  spanner                   2        2016-12-23  
34  hamsu       team     reflectors                2        2016-12-22  
35  27        engineer   cutting player            2,2      2016-12-22

如果我选择了更多tool_id s，那么也只显示一个值。这是我使用的代码，我的视图看起来像这样，我只在代码中显示了受影响的部分

<tbody>
    <?php $n=1;

        foreach($all_assign_tool_info as $row) {                              
            $t=explode(',',$row->tool_id);
            foreach($tools as $res) {
                foreach($t as $res1) {
                    if($res1==$res->id) {
                        $tool=$res->name;
                        //var_dump($tool);
                    }
                }
            }
        }                   

    ?>
    <tr>
        <td><?= $tool ?></td>
    </tr>
    <?php
    }?>
</tbody>

这是我的控制器

public function assign_tool($id = NULL)
{

    $data['all_assign_tool_info'] = $this->Tool_model->get_permission('tbl_tool_use');
    $data['tools']=$this->Tool_model->view_tools(null,null);
    $data['subview'] = $this->load->view('admin/tool/assign_tool',$data, TRUE);
    $this->load->view('admin/_layout_main', $data); //page load
}

我的模型看起来像这样

public function view_tools($limit,$offset)
{
    $this->db->order_by('id','desc');
    $query=$this->db->get('tbl_tools',$limit,$offset);
    return $query->result();
}

请帮我解决我的问题

这是新包含的代码我的tbl_tool_use表看起来像这样

id  user_id     type       tool_id     quantity    start_date  end_date
136  27         engineer    11,5,7      3,5,2      2016-12-22

表示tool_id 11为3，5为5，7为2 但结果如下5 3，7为5，11为2 得到的结果如下 Valid XHTML http://spdc.in/demo/spectra/spectra_tool.PNG 的

Answer 1

我会废除PHP中的迭代，并更专注于编写正确的SQL语法来获得结果。查看FIND_IN_SET和JOINS以使其发挥作用。基本上，您想要的是在逗号分隔值上连接两个表。我会以这种方式重写你的Codeigniter模型：

public function view_tools($limit,$offset)
{
    $this->db->select('tu.*, GROUP_CONCAT(t.name ORDER BY t.id) as tool_id', FALSE);
    $this->db->from('tbl_tools t');
    $this->db->join('tbl_tools_use tu', 'FIND_IN_SET(t.id, tu.tool_id)', 'inner', FALSE);
    $this->db->group_by('tu.id');
    $this->db->order_by('tu.id','desc');
    $this->db->limit($limit);
    $this->db->offset($offset);
    $query = $this->db->get();
    return $query->result();
}

获取存储为数组的值

1 个答案: