我想显示建议列表,其中仅包含以输入字符开头的单词而不包含包含输入字符的单词。
例如,假设我输入了L
,而不是显示像
["Launga Beach","Launga Hills","Launga Woods"]
不喜欢这个
["Echo Lake,"Fields Landing","Green Vally Lake"]
这是我的代码
ArrayAdapter<String> cityAdapter = new ArrayAdapter<String>(getActivity(),R.layout.auto_complete_select_dialog_item,mCityZipCodeMasterForCity.getCity());
cityAutoCompleteTextView.setThreshold(1);
cityAutoCompleteTextView.setAdapter(cityAdapter);
cityAutoCompleteTextView.setOnFocusChangeListener(new AutoCompleteTextValidator());
无论如何在android中自动完成textview中实现这个目的吗?
谢谢!
答案 0 :(得分:1)
下面我添加了示例Adapter
供您使用Custom
过滤器参考。
你只需要你的过滤逻辑。
CustomAdapter.java
import android.content.Context;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.Filter;
import java.util.ArrayList;
import java.util.List;
public class CustomAdapter extends ArrayAdapter<String> {
Context context;
int resource, textViewResourceId;
List<String> items, tempItems, suggestions;
public CustomAdapter(Context context, int resource, int textViewResourceId, List<String> items) {
super(context, resource, textViewResourceId, items);
this.context = context;
this.resource = resource;
this.textViewResourceId = textViewResourceId;
this.items = items;
tempItems = new ArrayList<String>(items); // this makes the difference.
suggestions = new ArrayList<String>();
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View view = convertView;
// Handle your layout here
return view;
}
@Override
public Filter getFilter() {
return nameFilter;
}
/**
* Custom Filter implementation for custom suggestions we provide.
*/
Filter nameFilter = new Filter() {
@Override
public CharSequence convertResultToString(Object resultValue) {
return resultValue.toString();
}
@Override
protected FilterResults performFiltering(CharSequence constraint) {
if (constraint != null) {
suggestions.clear();
// Here you can add your pattern like L* for starting string with 'L'
for (String item : tempItems) {
if (item.startsWith("your pattern here")) {
suggestions.add(item);
}
}
FilterResults filterResults = new FilterResults();
filterResults.values = suggestions;
filterResults.count = suggestions.size();
return filterResults;
} else {
return new FilterResults();
}
}
@Override
protected void publishResults(CharSequence constraint, FilterResults results) {
List<String> filterList = (ArrayList<String>) results.values;
if (results != null && results.count > 0) {
clear();
for (String item : filterList) {
add(item);
notifyDataSetChanged();
}
}
}
};
}
感谢。
答案 1 :(得分:0)
有String
的方法public boolean startsWith(String prefix)
示例
String text = "searching my text";
boolean value = text.startsWith("searching"); // return true
boolean value1 = text.startsWith("my"); // return false
忽略案例
boolean value = text.toLowerCase().startsWith("searching".toLowerCase());