Question

我有一个包含三个选项的表单：

适应
颜色
尺寸

默认情况下，“适合”下拉列表和“颜色”下拉列表处于活动状态且已选择默认值（例如常规适合和蓝色）。

有三种不同的“尺寸”下拉菜单，但根据从“适合”下拉菜单中选择的内容，任何时候都只能看到一个。

如果选项值=“无”，则禁用按钮。

问题

如果所有三个“尺寸”下拉列表都被更改以使其值不是“无”（仅通过选择常规的初始尺寸，然后从“适合”下拉列表中选择“小”和“长”，则“按钮”才会变为活动状态）。理想情况下，我只希望按钮考虑活动的“大小”下拉列表。

更新

下面是@nagappan提供的jsFiddle解决方案，非常感谢。

https://jsfiddle.net/dodgers76/c0dvdwbz/

var currentSelectedVals = {'selector-fit':'','selector-color':'','selector-sizes':''};
var disableComboVals = [
{'selector-fit':'','selector-color':'','selector-sizes':'none'},
{'selector-fit':'petite','selector-color':'','selector-sizes':'10'},
{'selector-fit':'petite','selector-color':'','selector-sizes':'20'},
{'selector-fit':'petite','selector-color':'','selector-sizes':'22'},
{'selector-fit':'petite','selector-color':'','selector-sizes':'24'},
{'selector-fit':'long','selector-color':'','selector-sizes':'22'},
{'selector-fit':'long','selector-color':'','selector-sizes':'24'}
];
function checkDisableCombo() {
return $.grep(disableComboVals, function(vals){
  cnt = 0;
  $.each(vals, function(key,val) {
     console.log('comparing key val '+key+val);
     if (val === '' || val === currentSelectedVals[key]) {
         console.log('>>matched values');
         cnt = cnt + 1;
     }
  });
  if (cnt===3) {
     return true;
  }
  return false;
});
};
$(function(){
var sizeVal = 'none';


  $("select.selector-fit").on("change", function(){
    //remove active
    $("select.selector-sizes.active").removeClass("active");
    //check if select class exists. If it does then show it
    var subList = $("select.selector-sizes."+$(this).val());
    if (subList.length){
      //class exists. Show it by adding active class to it
      subList.addClass("active");
      subList.val(sizeVal);
    }
  });

  $('.selector-sizes').on('change', function() {
    sizeVal = $(this).val();
  });
});

$(function() {
  $('.selector').on('change', function() {
    var $sels = $('option.selector-sizes:selected[value="none"]');
    var isSizeSelector = jQuery.inArray( "selector-sizes",this.classList);
    currentSelectedVals[this.classList[1]] = this.value;
    console.log(currentSelectedVals);
    var result = checkDisableCombo();
    console.log(result);
    if ( result.length > 0) {
        console.log('disabled false');
        $("#Testing").attr("disabled", true);
    } else {
        $("#Testing").attr("disabled", false);
    }
  }).change();
});

Answer 1

如果我们想要通过组合下拉选择的值来禁用按钮。我们可以有一个全局变量来跟踪三个下拉列表中当前选定的值。只有我们可以拥有一系列的分配组合。因此，无论何时用户选择一个值，我们都会与禁用组合交叉检查，如果匹配，我们可以禁用该按钮。验证组合可以如下完成。更新了jsfiddle链接。 JS FIDDLE UPDATED

import java.util.ArrayList;

public class Solution {
    public static int pathSum(TreeNode root, int sum) {
      return pathSum(root, sum, 0, new ArrayList<Integer>());
    }

    public static int pathSum(TreeNode root, int sum, int count, ArrayList<Integer> arr) {
        arr.add(root.val);
        int acc = 0;
        for (int i=arr.size()-1; i>=0; i--) {
          acc += arr.get(i);
          if (acc == sum)
            count++;
        }
        if(root.left != null)
            count = pathSum(root.left, sum, count, arr);
        if(root.right != null)
            count = pathSum(root.right, sum, count, arr);
        arr.remove(arr.size()-1);
        return count;
    }

  static class TreeNode {
    int val;
    TreeNode left;
    TreeNode right;
    public TreeNode(int v) {
      this.val = v;
    }
  }

  public static void main(String[] args) {
    TreeNode root = new TreeNode(10);
    root.left = new TreeNode(5);
    root.right = new TreeNode(-3);
    root.left.left = new TreeNode(3);
    root.left.right = new TreeNode(2);
    root.right.right = new TreeNode(11);
    root.left.left.left = new TreeNode(3);
    root.left.left.right = new TreeNode(-2);
    root.left.right.right = new TreeNode(1);
    System.out.println(pathSum(root, 8));
  }
}

由于隐藏的选择元素，按钮被禁用

1 个答案: