Question

我从URL获得了JSON REST API响应现在我无法解析JSON数据我尝试了很多解决方案但无法获得数据响应非常混乱，但它包含所需的数据所有JSON对象都在一个数组中。

以下是JSON响应：

[{"umeta_id":"1","user_id":"1","meta_key":"nickname","meta_value":"zfdz"},{"umeta_id":"2","user_id":"1","meta_key":"first_name","meta_value":""},{"umeta_id":"3","user_id":"1","meta_key":"last_name","meta_value":""},{"umeta_id":"4","user_id":"1","meta_key":"description","meta_value":""},{"umeta_id":"5","user_id":"1","meta_key":"rich_editing","meta_value":"true"},{"umeta_id":"6","user_id":"1","meta_key":"comment_shortcuts","meta_value":"false"},{"umeta_id":"7","user_id":"1","meta_key":"admin_color","meta_value":"fresh"},{"umeta_id":"8","user_id":"1","meta_key":"use_ssl","meta_value":"0"},{"umeta_id":"9","user_id":"1","meta_key":"show_admin_bar_front","meta_value":"true"}]

码“

if (jsonStr != null) {
    try {
        JSONObject jsonObj = new JSONObject(jsonStr);

        // Getting JSON Array node
        JSONArray contacts = jsonObj.getJSONArray("");

        // looping through All Contacts
        for (int i = 0; i < contacts.length(); i++) {
            JSONObject c = contacts.getJSONObject(i);

            String name = c.getString("umeta_id");
            String email = c.getString("user_id");
            String mobile = c.getString("meta_value");


            HashMap<String, String> contact = new HashMap<>();

            contact.put("name", name);
            contact.put("email", email);
            contact.put("mobile", mobile);

            // adding contact to contact list
            contactList.add(contact);
        }
    } catch (final JSONException e) {
        Log.e(TAG, "Json parsing error: " + e.getMessage());
        runOnUiThread(new Runnable() {
            @Override
            public void run() {
                Toast.makeText(getApplicationContext(),
                        "Json parsing error: " + e.getMessage(),
                        Toast.LENGTH_LONG)
                        .show();
            }
        });

    }
} else {
    Log.e(TAG, "Couldn't get json from server.");
    runOnUiThread(new Runnable() {
        @Override
        public void run() {
            Toast.makeText(getApplicationContext(),
                    "Couldn't get json from server. Check LogCat for possible errors!",
                    Toast.LENGTH_LONG)
                    .show();
        }
    });

}

JSON有效，我使用在线工具检查了它但我想在我的应用程序中使用数据我做错了什么？

Answer 1

首先。 jsonObj.getJSONArray(""); ...密钥不能是空字符串。^*

您的整个回复都是JSONArray，因为它以[字符而不是{开头，所以您不应该使用此

JSONObject jsonObj = new JSONObject(jsonStr);

但是你使用它，并删除另一行

JSONArray contacts = new JSONArray(jsonStr);

然后从那里开始你的for循环。

无法解析JSON REST API响应

1 个答案: