Question

目前，如果值仅包含单个数据而不是通过循环（如字符串数组），我已经通过将数据包装在Map数据类型中，成功地通过volley网络库发送字符串数据。我已经检查了地图内部的值并且所有数据都是正确的，但是当我尝试通过PHP发送数据时，我在mySQL中得到的东西都没有，在此之前结果只包含值的第一个字母。下面是我通过volley库的POST代码，以及用于从POST代码中获取值的PHP代码。

StringRequest stringRequest = new StringRequest(Request.Method.POST,     Register_URL, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            if (response.contains("Success")) {
                Toast.makeText(getApplicationContext(), "Success", Toast.LENGTH_SHORT).show();
            } else {
                Toast.makeText(getApplicationContext(), "Error", Toast.LENGTH_SHORT).show();
            }

        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            //Error Based on Volley
            Toast.makeText(getApplicationContext(), error.toString(), Toast.LENGTH_SHORT).show();
        }
    }) {

        @Override
        protected Map<String, String> getParams() throws AuthFailureError {
            Map<String, String> String_Map = new HashMap<String, String>();
            //User Data
            String_Map.put("Name", TIET_Register_Name.getText().toString());
            String_Map.put("Email", TIET_Register_Email.getText().toString());
            String_Map.put("Phone", TIET_Register_Phone.getText().toString());
            String_Map.put("Username", TIET_Register_Email.getText().toString());//Username = Email
            String_Map.put("Password", Password);
            if (ACTV_Parent.isChecked()) {//Parent
                String_Map.put("Status", "Parent");
                String_Map.put("Parent_Status", Spinner_Register_Parent.getSelectedItem().toString());
            } else if (ACTV_Teacher.isChecked()) {//Teacher
                String_Map.put("Status", "Teacher");
            } else {//Staff
                String_Map.put("Status", "Staff");
            }
            int i = 0;
            for (String Child_Name : Container_String) {
                String_Map.put("Child_Name[" + (i++) + "]", Child_Name);
            }
            return String_Map;
        }
    };
    Volley.newRequestQueue(getApplicationContext()).add(stringRequest);

<?php


//User Data
$name = $_POST['Name'];
$email = $_POST['Email'];
$phone = $_POST['Phone'];
$username = $_POST['Username'];
$password = $_POST['Password'];
$status = $_POST['Status'];
$p_status = $_POST['Parent_Status'];

//Child Data

//My suspect the problem lies between these three line. 
$child_name = $_POST['Child_Name'];
$child_bdate = $_POST['Born_Date'];
$child_gstat = $_POST['Graduation_Status'];

require_once('Connect.php');//Connect to Connect.php

//User Insert
$SQL_Insert = "INSERT INTO ms_user(NAME, EMAIL, PHONE, USERNAME, PASSWORD,  STATUS, PARENT_STATUS)
VALUES('$name', '$email', '$phone', '$username', '$password',  '$status', '$p_status')";

if(mysqli_query($Connect, $SQL_Insert)){

//Get user id
$Last_ID = "SELECT MAX(USER_ID) AS Temp_Value FROM ms_user";
$Query = mysqli_query($Connect, $Last_ID);
$Result = mysqli_fetch_assoc($Query);
$Fix = $Result['Temp_Value'];
}

//Insert child data
for($i = 0;$i<count($child_name);$i++){
$Child_SQL_Insert = "INSERT INTO ms_child(CHILD_NAME, BORN_DATE, GRAD_STAT, PARENT_ID)
VALUES('$child_name[i]', '$child_bdate[i]', '$child_gstat[i]', '$Fix')";
}
if(mysqli_query($Connect, $Child_SQL_Insert)){
    echo "Success";
}
else{
    echo "Failed";
}
?>

This is the result looks like in MySQL

将Map <string，string =“”>发送到PHP但是，PHP无法从Map获取字符串数组

0 个答案: