如何映射值？

Question

我想获取对象的具体信息，如果有以下内容，我该怎么做呢？ 我有javascript代码

        var data = {
        Id: null,
        Name_Product: null,
        Price: null,
        Description: null
    }
    $.ajax({
        url: '/editpr',
        type: 'POST',
        data: JSON.stringify({ id: tested }),
        contentType: "application/json; charset=utf-8",
        //dataType: 'JSON',
        success: function (data) {
            var Price = data.Price
            var newinput = document.createElement('input')
            newinput.className = 'save_inp'
            newinput.id = 'id_save_inp'
            newinput.value = Price
            $('.price').html(newinput)

并且必须从mvc controller返回值：

  public Products Editproducts([FromBody] int id)
    {       
      //  Products Product = null;
        DBEntities bd = new DBEntities();
        Products SenMes = bd.Products.Find(id);
        if (SenMes != null)
        {
            Products product = new Products
            {
                Id = SenMes.Id,
               Name_Product = SenMes.Name_Product,
                Description = SenMes.Description,
                Price = SenMes.Price,
                MesAndProduct = SenMes.MesAndProduct
            };
          // Product = SenMes;
            return product;
        }
        return null;
    }

但我的结果不好

Answer 1

当你这样做时，控制器会收到一个名为id的属性的对象，而不仅仅是整数。

一种方法是接受自定义类型（实际上任何具有名为id的int属性的可序列化类型都可以。）

class IntHolder
{
    public int id {get;set;}
}

public Products Editproducts([FromBody] IntHolder holder)
    {       
      //  Products Product = null;
        DBEntities bd = new DBEntities();
        Products SenMes = bd.Products.Find(holder.id);
        if (SenMes != null)
        {
            Products product = new Products
            {
                Id = SenMes.Id,
               Name_Product = SenMes.Name_Product,
                Description = SenMes.Description,
                Price = SenMes.Price,
                MesAndProduct = SenMes.MesAndProduct
            };
          // Product = SenMes;
            return product;
        }
        return null;
    }