Question

我正在尝试检索每个贷款号码，并计算每月贷款号码出现次数。所以在某些情况下，贷款数量在本月出现两次，但我只想在每个月计算一次。 TEST和RD专栏没有给我我需要的东西。这就是我所拥有的：

select 
[Month],
one,
LoanNumber,
two,
three,
four,
...

count(distinct LoanNumber) as TEST,
COUNT(LoanNumber) OVER () as RD

from

tableNAME LC
where [month] ='12-2016'
group by 
[Month],
one,
LoanNumber,
two,
three,
four,
...

请帮忙！

Answer 1

我认为您只需要在窗口count（）表达式中添加partition by子句，然后删除group by，如下所示：

select 
[Month],
one,
LoanNumber,
two,
three,
four,
...
COUNT(*) OVER (partition by Month, LoanNumber) as NumberOfOccurences

from

tableNAME LC
where [month] ='12-2016'

Answer 2

你需要从GROUP BY子句中取出LoanNumber。

另外，如果你想按月分组，而不是每月的每个loanNumber，请将它从SELECT子句中删除。

子查询中的COUNT（DISTINCT）

2 个答案: