带有Dense_Rank的Oracle语句（）Postgres中的第一个ODER BY

Question

有人可以告诉我如何在Postgres SQL中转换以下Oracle SQL语句吗？我不明白......

SELECT MIN(t2.id) KEEP (DENSE_RANK FIRST ORDER BY t2.edit_date) AS id 
  FROM temp t2 
 GROUP BY t2.sku

Answer 1

SELECT MIN(t2.id) OVER (ORDER BY t2.edit_date) AS id 
FROM temp t2 
GROUP BY t2.sku

修改

尽管上面提到了OP所要求的，但给定查询的等价物可以是：

select min(t.id) id 
from
  (select t.*,
   dense_rank() over (order by t.edit_date) AS rnk 
   from temp t) t
where rnk = 1
group by t.sku;