我是Firebase的新手。所以,我有一个像这样的数据库结构:
并希望将生成的ID显示在列表视图中。我使用的是FirebaseListAdapter。这是我的代码:
databaseReference = FirebaseDatabase.getInstance().getReference().child("Firebase").child("Users");
firebaseListAdapter = new FirebaseListAdapter<String>(this, String.class, android.R.layout.simple_list_item_1, databaseReference) {
@Override
protected void populateView(View v, String string, int position) {
TextView textView = (TextView) v.findViewById(android.R.id.text1);
textView.setText(string);
}
};
listView = (ListView) findViewById(R.id.listView);
listView.setAdapter(firebaseListAdapter);
这是我的用户类:
class User {
private String userName;
private String email;
void setUserName(String userName) {this.userName = userName;}
String getUserName() {return userName;}
void setEmail(String email) {this.email = email;}
String getEmail() {return email;}
}
当我复制此内容时,我收到此错误:com.google.firebase.database.DatabaseException: Failed to convert value of type java.util.HashMap to String
我该如何解决这个问题?
提前致谢!
答案 0 :(得分:1)
将populateView
方法实现更改为
firebaseListAdapter = new FirebaseListAdapter<User>(this, User.class, android.R.layout.simple_list_item_1, databaseReference) {
@Override
protected void populateView(View v, User user, int position) {
TextView textView = (TextView) v.findViewById(android.R.id.text1);
String userKey = this.getRef(position).getKey();
textView.setText(userKey);
}
};
答案 1 :(得分:0)
您需要FirebaseListAdapter<Map>
代替FirebaseListAdapter<String>
。你的代码会变成这样的东西(虽然没有编译它,但这取决于你; - )
databaseReference = FirebaseDatabase.getInstance().getReference().child("Firebase").child("Users");
firebaseListAdapter = new FirebaseListAdapter<Map>(this, Map.class, android.R.layout.simple_list_item_1, databaseReference) {
@Override
protected void populateView(View v, Map users, int position) {
TextView textView = (TextView) v.findViewById(android.R.id.text1);
textView.setText(users.getKey());
}
};
listView = (ListView) findViewById(R.id.listView);
listView.setAdapter(firebaseListAdapter);