Question

我想

SELECT DISTINCT column1, column2 as t1

我想

SELECT column3 FROM table2 WHERE column4 = "1" AND column3 = (matches)t1.column1

我的查询应该如何？

SELECT DISTINCT column1, column2 FROM table1 as t1,
column3 FROM table2 WHERE column4 = "1" AND column3 = t1.column1

结果应该是包含column1数据的列表，该列表与column3和column4 = 1

中的数据匹配

Table1:                Table2:
-----------------------------------------
column1    column2     column3    column4
-----------------------------------------
001        Name        001        1      
002        Name        002        0
003        Name        004        1
005        Name        005        1
-----------------------------------------
Result: 001, 005

错误：

语法错误或访问冲突：1064 SQL中有错误句法;检查与MariaDB服务器对应的手册正确使用语法的版本＆＃39; FROM table2 WHERE column4 = ＆＃39; 1＆＃39; AND column3 = t1.column1＆＃39;在第1行

Answer 1

select distinct
   t1.column1,
   t1.column2,
   t2.column4
from
   table1 as t1
inner join
   table2 as t2 on t2.column3 = t1.column1
where
   column4 = "1"

Answer 2

您的查询应如下所示：

SELECT DISTINCT
    t1.column1, t1.column2, t2.column3, t2.column4
FROM
    table1 AS t1,
    table2 AS t2
WHERE
    t2.column4 = '1'
        AND t2.column3 = t1.column1

mySQL从两个表中选择并匹配结果

2 个答案: