我正在尝试通过服务器发送文本文件的内容并将其发送到客户端
这是服务器
Socket server = new Socket(AddressFamily.InterNetwork,
SocketType.Stream, ProtocolType.Tcp);
IPEndPoint localEP = new IPEndPoint(IPAddress.Any, 9050);
server.Bind(localEP);
server.Listen(10);
Console.WriteLine("Waiting for Client...");
Socket client = server.Accept();
IPAddress clientAddress = ((IPEndPoint)client.RemoteEndPoint).Address;
Console.WriteLine("Got connection from " + clientAddress);
NetworkStream stream = new NetworkStream(client);
StreamReader reader = new StreamReader(stream);
StreamWriter writer = new StreamWriter(stream);
writer.WriteLine("Welcome to my test server");
writer.Flush();
string line = null;
while ((line = reader.ReadLine()).Length != 0)
{
Console.WriteLine("loooking for this file:" + line);
System.IO.FileInfo fi = new System.IO.FileInfo(line);
Console.WriteLine("Found");
writer.WriteLine("File Size: " + fi.Length + "\nContent:");
StreamReader tr = new StreamReader(line);
string s = null;
//string b = "";
while((s= tr.ReadLine()).Length != 0)
{
writer.WriteLine(tr.ReadLine());
writer.Flush();
}
tr.Close();
}
client.Close(); server.Close();
客户端从服务器读取的部分是
String line = null;
line = textBox3.Text;
writer.WriteLine(line); // Send line to Server
writer.Flush();
string s = null;
// Read line from server, then echo on the screen
while((s= reader.ReadLine()).Length != 0)
{
textBox4.Text += reader.ReadLine() + "\r\n\r\n";
}
当我运行代码时,根本没有错误,但是客户端卡住了,当我停止服务器时,文件的内容将显示,,, BTW,它是一个GUI应用程序
答案 0 :(得分:0)
while((s = reader.ReadLine())!= null){ textBox4.Text + = s; }
答案 1 :(得分:0)
Sample code for StreamReader使用下面的结构来检测流的结束。另外 - 你真的想在那个循环中读两行吗?
while (reader.Peek() >= 0)
{
s= reader.ReadLine();
textBox4.Text += s + Environment.NewLine + Environment.NewLine;
}
答案 2 :(得分:0)
您提到这是一个GUI应用程序?如果是这样,你正在阅读哪个帖子?如果您正在主线程上执行读取操作,那么应用程序消息循环将被冻结,并且在您停止另一方并终止连接之前不会显示任何内容。