我正在构建一个日期请求,我需要构建一个数组但是保持五周一周的格式,所以我可以轻松地将它输出到表格中。
我有这个当前工作日的数组,星期一到星期五,看起来像这样
$weekDays( [0] => 2016-12-19 [1] => 2016-12-20 [2] => 2016-12-21 [3] => 2016-12-22 [4] => 2016-12-23 )
和来自用户的数组,其中包含个性化日期
$user( [0] => 2016-12-20 [1] => 2016-12-21 [2] => 2016-12-22)
正如你所看到的,这只是本周五个日期中的三个。我需要合并日期匹配的这两个数组,但保持五天格式,如此
$userThisWeek([0] => NULL [1] => 2016-12-20 [2] => 2016-12-21 [3] => 2016-12-22 [4] => NULL)
我怎么能这样做?
答案 0 :(得分:1)
试试这个。
// $weekDays( [0] => 2016-12-19 [1] => 2016-12-20 [2] => 2016-12-21 [3] => 2016-12-22 [4] => 2016-12-23 );
// $user( [0] => 2016-12-20 [1] => 2016-12-21 [2] => 2016-12-22);
$userThisWeek = array();
foreach($weekDays as $key=>$value){
if (array_search($value, $user) === FALSE)
$userThisWeek[$key] = NULL;
else
$userThisWeek[$key] = $value;
}
答案 1 :(得分:0)
这样的事情:
$userThisWeek = [];
foreach ($weekDays as $key => $day) {
if (in_array($day, $user) {
$userThisWeek[$key] = $day;
} else {
$userThisWeek[$key] = null;
}
}