Question

class Grade(models.Model):
    name = models.CharField(u'年级', max_length=64)
    school = models.ForeignKey('School', verbose_name=u'学校')

    def __unicode__(self):
        return self.name

class Class(models.Model):
    name = models.CharField(u'班级', max_length=64)
    grade = models.ForeignKey('Grade', verbose_name=u'年级', related_name='grade')

    def getGradeName(self):
        return self.grade.name

    def __unicode__(self):
        return self.name

class Student(models.Model):
    name = models.CharField(u'姓名', max_length=64)
    sex = models.CharField(u'性别', max_length=64)
    id_num = models.CharField(u'身份证号', max_length=64)
    student_num = models.CharField(u'学号', max_length=64)
    class_id = models.ForeignKey('Class', verbose_name=u'班级', related_name='class_id')
    grade = class_id.name

    def __unicode__(self):
        return self.name

我想让学生上课，然后将其分配到模范学生的成绩。

如何在模特学生中获得成绩？

Answer 1

由于grade将是Class Student实例的grade，我建议您从Student删除Student类变量，而不是添加property到班级class Student(models.Model): name = models.CharField(u'姓名', max_length=64) sex = models.CharField(u'性别', max_length=64) id_num = models.CharField(u'身份证号', max_length=64) student_num = models.CharField(u'学号', max_length=64) class_id = models.ForeignKey('Class', verbose_name=u'班级', related_name='class_id') def __unicode__(self): return self.name @property def grade_name(self): return self.class.grade.name。像这样。

grade

要获取Student实例的student = Student.object.all()[0] grade = student.grade_name，它将是

services:
    user.default:
        class: \UserBundle\DefaultController

Answer 2

#get first student in table 
s = Student.object.all()[0]
# get Grade access through Class model
print s.class_id.grade

如何通过django中的外键访问一个模型中的其他模型属性？

2 个答案: