Question

 $ch = curl_init();   
 $curlConfig = array(
 CURLOPT_URL            => "http://localhost/staff/home.php",
 CURLOPT_POST           => true,
 CURLOPT_RETURNTRANSFER => true, 
 );
 curl_setopt_array($ch, $curlConfig); 
 $result = curl_exec($ch);
 curl_close($ch);
 $decodeData = json_decode($result);
 print_r($decodeData);

Answer 1

在文字使用的任何地方搜索字符串＆＃39;％＆＃39;：

$sql="SELECT * FROM test WHERE Name LIKE '%".trim($params['name'])."%'";

Answer 2

<?php   if (!empty($_REQUEST['fname'])){
                    $params['name']=$_REQUEST['salute']." ".$_REQUEST['fname']." ".$_REQUEST['lname'];
                    $sql="SELECT * FROM test WHERE Name LIKE '%".trim($params['name'])."%'";  

                    $records=mysqli_query($db->conn,$sql);
                            while($row=mysqli_fetch_assoc($records)){ ?>

Answer 3

要进行搜索，您必须在查询中添加％标记：

$sql="SELECT * FROM test WHERE Name LIKE '%".trim($params['name'])."%'";

尝试一下，如果可行，别忘了标记为正确。

如何使用php和mysql创建搜索表单

3 个答案: