Question

我输入的密码为UITextField 我的要求是当textField字符范围达到第6个字符然后我进行服务器验证时我必须将数据放入标签中。如果字符范围小于5，那么我将传递nil值。

以下是我的代码： -

//TextField character range
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

    if textField == pinCode
    {
        guard let text = textField.text else { return  true }

        let newLength = text.characters.count + string.characters.count - range.length
        if(5 >= newLength)
        {
            print(newLength)
        }

        else
        {
            if newLength == 6
            {
                serverValidation()

                print(textField.text!)
                setFields(city: "Ajmer", state: "Rajasthan", country: "India")
                return newLength <= 6
            }
            else
            {
                 return newLength <= 6
            }
        }

    }

    return true
}

我的问题是什么时候（newLength == 6）然后我只得到5个字符的textField文本。我的意思是如果假设邮政编码是560068那么文字我只得到56006。（但我在这种情况下只对6个字符的邮政编码进行服务器验证）

所以，如果（newLength == 6）那么如何在文本字段中获得6个字符，然后我只能在这里进行服务器验证。

我是斯威夫特的新人。

由于

Answer 1

在获取shouldChangeCharactersIn

中的实际文本之前，会先调用

UITextField

这是您从UITextField

获取全文的方法

let newString = NSString(string: textField.text!).replacingCharacters(in: range, with: string)

修改

这就是你如何使用它

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool { if textField == pinCode { guard let text = textField.text else { return true } let newString = NSString(string: textField.text!).replacingCharacters(in: range, with: string) let newLength = newString.characters.count if(5 >= newLength) { print(newLength) } else { if newLength == 6 { serverValidation() print(newString) setFields(city: "Ajmer", state: "Rajasthan", country: "India") return newLength <= 6 } else { return newLength <= 6 } } } return true }

Answer 2

使用 TextField 委托方法。

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

 let currentCharacterCount = textField.text?.characters.count ?? 0
            if (range.length + range.location > currentCharacterCount+1)
            {
                return false
            }

            print(currentCharacterCount)
            let newLength = currentCharacterCount + string.characters.count - range.length
            return newLength <= 6 //this will not allow you to enter more than 6 characters 

}

之后的电话

func textFieldDidEndEditing(_ textField: UITextField)
 {
             print(textField.text!)
            setFields(city: "Ajmer", state: "Rajasthan", country: "India")
}

要调用此方法，您可以使用view.endEditing(true)方法。

Answer 3

您应该从08 35 // 1: [u]int32, = 53 15 60485958 // 2: fixed32, = 1615354200 18 40 // 3: [u]int32, = 64 22 0a 0d6048595815bdf42642 // 4: sub-message, length 10 0d 60485958 // 1: fixed32, = 1615354200 15 bdf42642 // 2: fixed32, = 3186894402 2a 0a 0d7047595815bdf426 // 5: sub-message, length 10, incomplete 0d 70475958 // 1: fixed32, = 1883724120 15 bdf426 // 2: fixed32, incomplete + newlength

获取textfield.text.length

然后从string.length + textfield.text获取文字。

在调用return true之前，您无法从string获取新文本。

Answer 4

试试这个

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

if textField == pinCode
{
    guard let text = textField.text else { return  true }

    var txtAfterUpdate:NSString = textField.text! as NSString
    txtAfterUpdate = txtAfterUpdate.stringByReplacingCharactersInRange(range, withString: string)
    let txtString = txtAfterUpdate as String

    let newLength = txtString.characters.count
    if(5 >= newLength)
    {
        print(newLength)
    }

    else
    {
        if newLength == 6
        {
            print(textField.text!)
            setFields(city: "Ajmer", state: "Rajasthan", country: "India")
            return newLength <= 6
        }
        else
        {
            return newLength <= 6
        }
    }

}

return true
}

如何获取textField文本的范围直到6个字符？

4 个答案: