Question

嘿，第一次提问者希望这是正确的格式

我有一个python scirpt，它试图在这种情况下使用bash命令telnet 这是剧本

import subprocess

proc = subprocess.Popen(['/bin/bash'], stdin=subprocess.PIPE, stdout=subprocess.PIPE)
stdout = proc.communicate('telnet 192.168.1.67 5555')
print (stdout)

我的另一台机器上有一个脚本，在端口5555上侦听并在bash中调用脚本返回

Connection closed by foreign host.
("Trying 192.168.1.67...\nConnected to 192.168.1.67.\nEscape character is '^]'.\n", None

我的另一台计算机识别出一个连接，但它会立即关闭连接而当我运行命令

telnet 192.168.1.67 5555

它工作正常并保持连接打开

我的问题是如何编写一个与命令“telnet 192.168.1.67 5555”相同的脚本并保持连接打开？

Answer 1

您可以使用socket — Low-level networking interfac

请参阅本周关于socket的Python模块。

Python 2示例：

import socket, select, string, sys

if(len(sys.argv) < 3) :
    print 'Usage : python telnet.py hostname port'
    sys.exit()

host = sys.argv[1]
port = int(sys.argv[2])

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.settimeout(2)

# connect to remote host
try :
    s.connect((host, port))
except :
    print 'Unable to connect'
    sys.exit()

print 'Connected to remote host'

while 1:
    socket_list = [sys.stdin, s]

    # Get the list sockets which are readable
    read_sockets, write_sockets, error_sockets = select.select(socket_list , [], [])

    for sock in read_sockets:
        #incoming message from remote server
        if sock == s:
            data = sock.recv(4096)
            if not data :
                print 'Connection closed'
                sys.exit()
            else :
                #print data
                sys.stdout.write(data)

        #user entered a message
        else :
            msg = sys.stdin.readline()
            s.send(msg)

python处理脚本没有返回与直接bash命令相同的答案

1 个答案: