在数组索引中搜索超过某个值的出现次数

Question

感谢Jonathan Kuhn，我已更新此主题以反映您的建议。

我有以下数组，它只是名为$ array

Array
(
    [0] => Array
        (
            [id] => 10213
            [branch] => 1
            [parent] => 10183
            [age] => 53
        )

    [1] => Array
        (
            [id] => 10230
            [branch] => 1
            [parent] => 10213
            [age] => 22
        )

    [2] => Array
        (
            [id] => 10232
            [branch] => 1
            [parent] => 10213
            [age] => 17
        )

    [3] => Array
        (
            [id] => 10234
            [branch] => 1
            [parent] => 10232
            [age] => 6
        )

    [4] => Array
        (
            [id] => 10223
            [branch] => 2
            [parent] => 10183
            [age] => 31
        )

    [5] => Array
        (
            [id] => 10231
            [branch] => 3
            [parent] => 10183
            [age] => 19
        )

    [6] => Array
        (
            [id] => 10260
            [branch] => 3
            [parent] => 10231
            [age] => 22
        )

    [7] => Array
        (
            [id] => 10261
            [branch] => 3
            [parent] => 10231
            [age] => 16
        )
)

[branch]表示家谱顶部的人的原始子项。

因此，例如，我想循环并能够搜索$ array，以查找同时位于[branch] =＆gt;的“21”年龄的所有人的总数。等等

感谢任何帮助，谢谢！

Answer 1

您可以使用array_filter()，应用您的条件并获取结果数组的大小：

$foo = array_filter($array, function($a) {
    return $a["age"] > 21 && $a["branch"] == 1;
});

echo(count($foo));