我有一个包含一系列字符的字节数组。在一个案例中我有
<link href="https://cdnjs.cloudflare.com/ajax/libs/normalize/5.0.0/normalize.min.css" rel="stylesheet"/>28到31的字符“name”，该部分以元素32结尾。然后我有另一个字节数组：
[28] = 0x6e
[29] = 0x61
[30] = 0x6d
[31] = 0x65
[32] = 0x00
[33] = 0x00
[34] = 0x00
[35] = 0x4f
[36] = 0x08
[37] = 0x00
[38] = 0x07
[39] = 0x00
[40] = 0x00
[41] = 0x04
[42] = 0x13
[43] = 0xff
[44] = 0xff
[45] = 0x00
[46] = 0x00
我认为我有字符串[47] = 0x01
[48] = 0x03
[49] = 0x00
[50] = 0x00
[51] = 0x73
[52] = 0x65
[53] = 0xc3
[54] = 0xb1
[55] = 0x6f
[56] = 0x72
[57] = 0x00
[58] = 0x00
[59] = 0x00
[60] = 0x4f
[61] = 0x08
[62] = 0x00
[63] = 0x08
[64] = 0x00
[65] = 0x00
[66] = 0x04
[67] = 0x13
[68] = 0xff
[69] = 0xff
[70] = 0x00
[71] = 0x00
。
使用第一个数组，很容易找到名称作为前4个字节，señor作为终结符但是如何解释第二个字节数组上的什么？
两个数组都是00 s。
答案 0 :(得分：1)
该文字显然使用#!/bin/bash
declare -A possible_alias_names=(
["y"]="yes"
)
for item in "${!possible_alias_names[@]}"; do
if ! hash ${item} 2> /dev/null; then
if hash ${item} 2> /dev/null; then
echo "always enter here because the command ${item} is not available"
fi
alias_cmd1="${item}"
alias_cmd2="${possible_alias_names[$item]}"
eval "alias ${alias_cmd1}='${alias_cmd2}'"
#I also tried... eval "alias ${alias_cmd1}=\'${alias_cmd2}\'"
if hash ${item} 2> /dev/null; then
echo "You win!! alias worked. It means ${item} is available"
fi
fi
done
编码：
UTF-8这是UTF-8 encoded ñ字符。周围的字符是[53] = 0xc3
[54] = 0xb1
中的其余四个字符。
C ++库确实有working with UTF-8的一些功能;但我总觉得那些图书馆类有点笨拙和不灵活。在大多数平台上，您拥有一个出色，灵活的iconv library，其中包含一个简单易用的API，可用于在UTF-8和其他编码之间进行转换。