我在这个问题之前问过......
我想在我的网络中测试TCP套接字行为，因为我需要测试我的Java应用程序......
我使用Threads ...
创建了一个Server Client Model Example这里是ConsumerServer
public class ConsumerServer extends Thread {
private ServerSocket SrvrScktConsumer;
Socket clientSocket = null;
private boolean isConsumerRunning = false;
public ConsumerServer(int ConsPort) {
try {
SrvrScktConsumer = new ServerSocket(ConsPort);
System.out.println(NL + "ConsumerServer Listening on port number: " + ConsPort);
} catch (IOException e) { }
}
@Override public void run() {
try {
clientSocket = SrvrScktConsumer.accept();
InputStream input;
byte[] innerBytes = new byte[1024];
try {
input = clientSocket.getInputStream();
Integer iRemotePort = clientSocket.getPort();
String sRemoteHost = clientSocket.getInetAddress().getHostAddress();
System.out.println("ConsumerServer: Remote Connection\n\tPort:" + iRemotePort+ " Host:" + sRemoteHost);
isConsumerRunning = true;
while (isConsumerRunning) {
try {
byte[] incomingBytes = Arrays.copyOf(innerBytes, input.read(innerBytes));
jtaMessages.append(NL + "Consumer GET " + new String(incomingBytes));
jtfLastReceived.setText(new String(incomingBytes));
} catch (IOException | NegativeArraySizeException | IndexOutOfBoundsException e) {
isConsumerRunning = false;
}
}
System.out.println(NL + "ConsumerClient closing from Host " + sRemoteHost + " Port " + iRemotePort);
try { if (input != null) input.close(); } catch (IOException e) { }
} catch (IOException e) {
System.out.println(NL + "Error Creating ConsumerClient\n\t:" + e.toString());
}
} catch (IOException | NullPointerException e) {
System.out.println(NL + "ConsumerServer Stopped: " + e.toString()) ;
}
System.out.println(NL + "Exiting ConsumerServer...");
}
public void stopServer() {
try {
SrvrScktConsumer.close();
} catch (IOException | NullPointerException e) { }
try {
clientSocket.close();
} catch (IOException | NullPointerException e) { }
isConsumerRunning = false;
}
};
这里是ProducerClient
public class ProducerClient extends Thread {
private Socket clientSocket = null;
private OutputStream output = null;
private boolean isProducerRunning = false;
public ProducerClient(String ConsHost , int ConsPort) {
try {
clientSocket = new Socket(ConsHost, ConsPort);
output = clientSocket.getOutputStream();
System.out.println(NL + "ProducerClient Connected to port number: " + ConsPort);
}
catch (IOException e) { }
}
@Override public void run() {
if (!(clientSocket == null)) {
Integer iLocalPort = clientSocket.getLocalPort();
String sLocalHost = clientSocket.getLocalAddress().getHostAddress();
System.out.println("ConsumerServer: Local Connection\n\tPort:" + iLocalPort+ " Host:" + sLocalHost);
int ctrlPrintOut = 0, ctrlPrintIn = 0;
isProducerRunning = true;
while (isProducerRunning) {
try {
if (bProducerReady) {
bProducerReady = false;
output.write(jtfSendMessage.getText().getBytes());
jtaMessages.append(NL + "Producer PUT " + jtfSendMessage.getText());
jtfSendMessage.setText("");
}
// // Ini Code Block to delete
// else {
// try {
// Thread.sleep(1);
// } catch (InterruptedException ex) { }
// if (ctrlPrintOut == 1000000 /*Integer.MAX_VALUE*/) {
// if (ctrlPrintIn == 2) {
// System.out.println("ProducerClient Waiting!");
// ctrlPrintIn = 0;
// }
// ctrlPrintIn++; ctrlPrintOut = 0;
// }
// ctrlPrintOut++;
// }
// // End Code Block to delete
} catch (IOException e) {
System.out.println("ProducerClient: " + e.toString());
isProducerRunning = false;
}
}
try { output.close(); } catch (IOException e) { }
try { clientSocket.close(); } catch (IOException e) { }
System.out.println(NL + "Exiting ProducerClient...");
}
}
public void stopClient() {
try {
clientSocket.close();
} catch (IOException | NullPointerException e) { }
isProducerRunning = false;
}
};
我想删除指示的块代码，但是当我删除..我的测试无法正常工作。
这里使用类之前的类
public class ClientServerShort extends JFrame {
private JButton jbSendMessage = new JButton("Send Message");
private JLabel jlLastReceived = new JLabel("Last Received");
private JTextArea jtaMessages = new JTextArea(5,20);
private JScrollPane jspMessages = new JScrollPane(jtaMessages);
private JToggleButton jtbConsumer = new JToggleButton("Launch Consumer Server");
private JToggleButton jtbProducer = new JToggleButton("Launch Producer Client");
private JTextField jtfLastReceived = new JTextField();
private JTextField jtfSendMessage = new JTextField();
static boolean bProducerReady = false;
static final String NL = System.getProperty("line.separator");
ConsumerServer thrdConsumerServer = null;
ProducerClient thrdProducerClient = null;
public ClientServerShort() {
setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
jbSendMessage.addActionListener((ActionEvent evt) -> {
if (!jtfSendMessage.getText().isEmpty()) {
bProducerReady = true;
}
});
jlLastReceived.setBorder(BorderFactory.createEtchedBorder());
jlLastReceived.setHorizontalAlignment(SwingConstants.CENTER);
jtbConsumer.addActionListener((ActionEvent evt) -> {
if (jtbConsumer.isSelected()) {
if (thrdConsumerServer == null) {
thrdConsumerServer = new ConsumerServer(1027);
thrdConsumerServer.start();
}
} else {
if (thrdConsumerServer != null) {
thrdConsumerServer.stopServer();
thrdConsumerServer = null;
}
}
});
jtbProducer.addActionListener((ActionEvent evt) -> {
if (jtbProducer.isSelected()) {
if (thrdProducerClient == null) {
thrdProducerClient = new ProducerClient("192.168.0.49", 1027);
thrdProducerClient.start();
}
} else {
if (thrdProducerClient != null) {
thrdProducerClient.stopClient();
thrdProducerClient = null;
}
}
});
jtfLastReceived.setEditable(false);
JPanel jpMessagesUp = new JPanel();
jpMessagesUp.setLayout(new GridLayout(2, 2, 6, 6));
jpMessagesUp.add(jbSendMessage);
jpMessagesUp.add(jtfSendMessage);
jpMessagesUp.add(jlLastReceived);
jpMessagesUp.add(jtfLastReceived);
getContentPane().setLayout(new BoxLayout(getContentPane(), BoxLayout.PAGE_AXIS));
add(jtbProducer);
add(jtbConsumer);
add(jpMessagesUp);
add(jspMessages);
pack();
}
public static void main(String args[]) {
EventQueue.invokeLater(() -> {
new ClientServerShort().setVisible(true);
});
}
}
问题：
是什么原因，为什么我删除了指示代码段（在ProducerClient中），我的单个应用程序不起作用？
答案 0 :(得分：0)
原因正是我在你的另一个问题中告诉你的。 bProducerReady需要volatile，因为您正在从不同的线程中读取和写入它。你的奇怪的延迟代码只是经过一段时间才能完成相同的内存刷新。
注意它不需要是static。
为什么你转发这个已回答的问题仍然是一个谜。