根据table1中的匹配项和table2中的不匹配项将数据插入table3

Question

想要制作简单的Lost and Found数据库。我有table2（在系统中添加）＆＃34; costumer＆＃34;进来并定义＆＃34; ztracena _ / _ nalezea＆＃34; 0表示丢失，1表示发现。 然后他更多地指出table1中的东西，如重量，颜色等...... 现在我想用这两个数据填充table3（匹配）。我需要在table2中匹配，但我需要这些东西是一个丢失0和一个找到1（table2）。 真的希望我解释得足够简单。感谢帮助！

Answer 1

如果您能提供样本数据和所需结果，那将会容易得多。我认为这样做你想要的：

with t1 as (
  select 1 as flag, 1 as id from dual union all
  select 1 as flag, 2 as id from dual union all
  select 0 as flag, 3 as id from dual union all
  select 0 as flag, 4 as id from dual
), t2 as (
  select 1 as id, 'yellow' as color, 'hat' as category from dual union all
  select 2 as id, 'red' as color, 'box' as category from dual union all
  select 3 as id, 'yellow' as color, 'hat' as category from dual union all
  select 4 as id, 'red' as color, 'hat' as category from dual
)
select tflag0.id || ' matches ' || tflag1.id from 
  (select t1.id, t2.color, t2.category from t1  inner join t2 on (t1.id = t2.id) where flag = 0) tflag0 --things lost
  inner join 
  (select t1.id, t2.color, t2.category from t1  inner join t2 on (t1.id = t2.id) where flag = 1) tflag1 --things found
  on (tflag0.color = tflag1.color and tflag0.category = tflag1.category);

第一部分将t1定义为您的表格，我们在t2中放置了意味着找到/丢失的内容，我们对事物进行了描述。查询为id t1提供了.tiles-menu{ width:1024px; margin:auto; } .tiles-menu .submenu-menu .views-row{ float:left; } .tilesImage , .tilesTitle{ margin:auto; } .innerPageTilesMenu{ padding:4%; }个相同的描述，一个人找到了它，另一个人丢失了它。现在请尝试使解决方案适应您的模型。