我在代码下面运行以生成' .min'本地文件及其工作正常但它在服务器上不起作用。代码中有什么问题吗?
var fs = require('fs'),
es = require('event-stream'),
gulp = require('gulp'),
compass = require('gulp-compass'),
concat = require('gulp-concat'),
jshint = require('gulp-jshint'),
scsslint = require('gulp-scsslint'),
sourcemaps = require('gulp-sourcemaps'),
uglify = require('gulp-uglify');
minifyCSS = require('gulp-minify-css');
JavaScript任务:
gulp.task('javascript', function(){
gulp.src('js/animation.js')
.pipe(concat('js/animation.min.js'))
.pipe(uglify())
.pipe(gulp.dest(''));
});
gulp.task('style', function(){
gulp.src(['css/transition.css'])
.pipe(concat('css/transition.min.css'))
.pipe(minifyCSS())
.pipe(gulp.dest(''));
});
观看文件:
gulp.task('watch', ['build'], function() {
gulp.watch(['css/transition.css'], ['style']);
gulp.watch(['js/animation.js'], ['javascript']);
});
任务套装:
gulp.task('build', [
'css','js'
]);
gulp.task('default', ['watch','build']);