Question

我想在我的应用程序运行时调暗手机屏幕，如果在一段时间内（例如10秒）没有触摸事件，则在屏幕上的任何地方再次触摸时使屏幕更亮。< / p>

搜索SO后，似乎我需要创建自定义<section id="content"> <div class="container" data-ng-controller="tableUserCtrl"> <div class="p-t-0" data-ng-controller="ModalDemoCtrl"> <script type="text/ng-template" id="adduser.html"> <div class="modal-header">  </div> <form role="form" ng-submit="insertInfo(userInfo);" name="userForm" novalidate> ... <div class="modal-footer"> <button class="btn btn-link" ng-click="ok(); $parent.addUserT(user);" ng-disabled="userForm.$invalid">Submit</button> <button class="btn btn-link" ng-click="cancel()">Cancel</button> </div> </form> </script> <button class="btn btn-default pull-right" ng-click="openStatic('adduser')">Add User</button><br/><br/> </div> <div class="card"> <div class="card-header"> <h2>Users <small></small></h2> </div> <div class="card-body"> <div class="table-responsive"> <table ng-table="tableEdit" class="table table-striped table-vmiddle" show-filter="true"> <tr ng-repeat="w in $data" ng-class="{ 'active': w.$edit }"> <td data-title="'ID'" filter="{ 'role_no': 'text' }" sortable="'role_no'"> <span ng-if="!w.$edit">{{ w.role_no }}</span> <div ng-if="w.$edit"><input class="form-control" type="text" ng-model="w.role_no" /></div> </td> ... <td data-title="'Actions'"> <button type="button" class="btn btn-default" ng-if="!w.$edit" ng-click="w.$edit = true"><i class="zmdi zmdi-edit"></i></button> <button type="button" class="btn btn-default" ng-if="!w.$edit" ng-click="removeUser(w.user_id, w)"><i class="zmdi zmdi-close"></i></button> <button type="button" class="btn btn-success" ng-if="w.$edit" ng-click="w.$edit = false; updateUser(w)"><i class="zmdi zmdi-check"></i></button> </td> </tr> </table> </div> </div> </div> </div> </section>才能处理所有触摸。以下是我目前的代码：

UIApplication

打印输出看起来像这样：

import UIKit

@objc(MyApplication)

class MyApplication: UIApplication {

    override func sendEvent(_ event: UIEvent) {

        var screenUnTouchedTimer = Timer.scheduledTimer(timeInterval: 10, target: self, selector: #selector(self.makeScreenDim), userInfo: nil, repeats: true);

        // Ignore .Motion and .RemoteControl event simply everything else then .Touches
        if event.type != .touches {
            super.sendEvent(event)
            return
        }

        // .Touches only
        var restartTimer = true
        if let touches = event.allTouches {
            // At least one touch in progress? Do not restart timer, just invalidate it
            self.makeScreenBright()
            for touch in touches.enumerated() {
                if touch.element.phase != .cancelled && touch.element.phase != .ended {
                    restartTimer = false
                    break
                }
            }
        }

        if restartTimer {
            // Touches ended || cancelled, restart timer
            print("Touches ended. Restart timer")
        } else {
            // Touches in progress - !ended, !cancelled, just invalidate it
            print("Touches in progress. Invalidate timer")
        }

        super.sendEvent(event)
    }

    func makeScreenDim() {
        UIScreen.main.brightness = CGFloat(0.1)
        print("makeScreenDim")
    }

    func makeScreenBright() {
        UIScreen.main.brightness = CGFloat(0.5)
        print("makeScreenBright")
    }
}

正如您在上面看到的那样，代码存在很大问题，似乎我正在为每个触摸事件创建一个新的Timer。我不知道如何在UIApplication中创建一个静态（只有一个）Timer。

我应该如何以正确的方式只实现一个计时器？

（我正在使用Iphone7，最新版本的swift和xcode）

Answer 1

您必须在某处使先前创建的计时器无效，否则您将获得所描述的行为。

在每次调用sendEvent时将其存储在属性中，以便下次调用该方法时可以访问它。

class MyApplication: UIApplication {

var screenUnTouchedTimer : Timer?

override func sendEvent(_ event: UIEvent) {

screenUnTouchedTimer?.invalidate()
screenUnTouchedTimer = Timer ......

当应用程序暂时不使用时，将显示屏调暗

1 个答案: