我的Laravel应用程序中有2个表,即客户和商店。客户可以属于许多商店,商店可以拥有许多客户。它们之间有一个数据透视表来存储这种关系。
问题是,如何使用Eloquent提取给定商店的客户列表?可能吗?我目前能够使用Laravel的查询生成器来提取它。这是我的代码:
| customers | stores | customer_store |
-------------------------------------------
| id | id | customer_id |
| name | name | store_id |
| created_at| created_at | created_at |
| updated_at| updated_at | updated_at |
客户模式:
public function stores(){
return $this->belongsToMany(Store::class)
->withPivot('customer_store', 'store_id')
->withTimestamps();
}
商店模式:
public function customers(){
return $this->belongsToMany(Customer::class)
->withPivot('customer_store', 'customer_id')
->withTimestamps();
}
数据库查询(使用查询生成器):
$customer = DB::select(SELECT customers.id, customers.name, customers.phone, customers.email, customers.location FROM customers LEFT JOIN customer_store on customers.id = customer_store.customer_id WHERE customer_store.store_id = $storeID);
答案 0 :(得分:10)
试试这个:
public function result(Request $request) {
$storeId = $request->get('storeId');
$customers = Customer::whereHas('stores', function($query) use($storeId) {
$query->where('stores.id', $storeId);
})->get();
}
答案 1 :(得分:2)
尝试执行此操作......
$result = Customer::with('stores')->get();
希望这有帮助。
要了解有关雄辩关系的更多信息,请参阅:https://laravel.com/docs/5.1/eloquent-relationships
答案 2 :(得分:-1)
尝试以下:
此处Customers
是您的模型,$storeID
是您的商店ID。 $storeID
超出了回调范围。所以你必须使用use语句来传递它们。
Customers::leftJoin('customer_store', function($join) use($storeID){
$join->on('customers.id', '=', 'customer_store.customer_id')
->where('customer_store.store_id','=', $storeID);
})
->whereNotNull('customer_store.store_id')//Not Null Filter
->get();
希望这对你有帮助!