Question

我有这个错误，我似乎无法解决。

这是代码

$this->stmt = $this->handle->prepare("SELECT * FROM tb_ph WHERE totalprofit = 0 AND status = '1' AND checks = ''");

$var = $this->stmt->fetchAll();

$var返回一个多维数组，我喜欢循环，以获得各自的id和用户名。现在的问题是，如果我做

foreach($var as $key => $value){
    $id = $value['id'];
    $username = $value['username'];
    $phone = $value['phone'];
}

我收到通知：数组到字符串转换错误。

var_dump($var)给出了

Array
(
    [0] => Array
        (
            [id] => 3
            [0] => 3
            [username] => rose
            [1] => rose
            [phone] => +2782345578952
            [2] => +2782345578952 
        )

    [1] => Array
        (
            [id] => 4
            [0] => 4
            [username] => josh
            [1] => rose
            [phone] => +0182345578952
            [2] => +0182345578952 
        )

)

每次返回两个结果时，如何使循环只获取id，用户名和电话？

Answer 1

非常仔细地看这一点：

Array
(
    [0] => Array
        (

它向您显示您所拥有的是一个数组数组，因此您的foreach中的内容是另一个数组

foreach($var as $arr) {
    /* here $arr is an array in calling print on it will produce the warning you have already seen but ...*/
    print $arr[$id];

}

因为这里只打印一个数组元素。同样打印$ arr ['username']

注意：PDO中的数组转换为字符串

1 个答案: