Question

我设法将输入保存到变量中，然后在它下面的函数中调用它。我想考虑.upper（）和.lower（）选项，例如是否有人输入＆＃34; C＆＃34;，＆＃34; c＆＃34;，＆＃34; Circle＆＃34;或＆＃ 34;圆＆＃34 ;.不知道如何做到这一点......

"""
a calculator that can compute the area of a chosen shape, as selected by the user. The calculator will be able to determine the area of a circle or a triangle
"""

from math import pi
from time import sleep
from datetime import datetime

#opening comments and thinking computer thinks for 1 second
now = datetime.now()
print("Calculator is booting up! Beep Boop...")
print(("%s/%s/%s " + "%s:%s \n") % (now.month, now.day, now.year, now.hour, now.minute))
sleep(1)

#nagging teacher comment if needed 
hint = str("Don\'t forget to include the correct units! \nExiting...")

#user input choose Circle or Triangle
option = input("Enter C for Circle or T for Triangle: ")

#Circle computing
if (option.upper() == input(str(C))) or (option.lower() == input(str(c))):
  radius = input(float("What is the radius?: "))
  area = (pi * radius ** 2)
  print("The pie is baking...")
  sleep(1)
  print(str(area + hint))

来自代码学院的项目并尝试搜索答案，但在这里找不到答案

Answer 1

只需降低您从用户那里获得的输入，并仅针对小写进行测试：

if option.lower() == expected_lowercase_input:

这样您就不必担心案件'FOO'，'Foo'，'fOO'等等都会降低到'foo'。

要考虑'c'或'circle'等变体，您可以执行以下操作：

expected = ('c', 'circle')

if option.lower() in expected:
    ...

如果if的小写版本为option 或 'c'，则会执行'circle'阻止。

坚持Codecademy的东西。在我看来，这是一个很好的资源！

设置用户输入参数并考虑不同的答案

1 个答案: