我使用文件上传PHP将文件从用户输入表单获取到正确的路径：
@connect((store) => {
return {
...store
}
})
export default class SomeComponent extends React.Component {
...
处理<form method="post" action="form_action1.php" enctype="multipart/form-data">
<div class="form-group">
<label for="attachment1">Add file(s)</label>
<input type="file" class="form-control-file" id="attachment1" aria-describedby="fileHelp" name="attachment1">
<input type="file" class="form-control-file" id="attachment2" aria-describedby="fileHelp" name="attachment2">
<input type="file" class="form-control-file" id="attachment3" aria-describedby="fileHelp" name="attachment3">
<small id="fileHelp" class="form-text text-muted">PDFs, Word Docs or images (PNG, JPG, etc.) Maximum 16 MB. </small>
</div>
</form>
的PHP脚本部分是：
$_FILES文件上传到正确的位置，但不会将路径上传到SQL表。有人告诉我，我的脚本需要刷新查询，但它让我不知所措。
另外，我有多个文件上传区域。我可以<?php
$servername = "localhost";
$username = "jobs_usr1";
$password = "XXXXXXXX";
try {
$conn = new PDO("mysql:host=$servername;dbname=jobs_users", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
if(isset($_POST['submit']) && !empty($_POST['submit'])) {
$job_name=$_POST['job_name'];
$comments=$_POST['comments'];
$attachment1=$_POST['attachment1'];
$attachment2=$_POST['attachment2'];
$attachment3=$_POST['attachment3'];
$due_date=$_POST['due_date'];
$requestor=$_POST['requestor'];
$req_email=$_POST['req_email'];
$property=$_POST['property'];
}
if(isset($_FILES['attachment1'])){
$errors= array();
$file_name = $_FILES['attachment1']['name'];
$file_size = $_FILES['attachment1']['size'];
$file_tmp = $_FILES['attachment1']['tmp_name'];
$file_type = $_FILES['attachment1']['type'];
$file_ext=strtolower(end(explode('.',$_FILES['attachment1']['name'])));
$expensions= array("jpeg","jpg","png","doc","pdf");
if(in_array($file_ext,$expensions)=== false){
$errors[]="extension not allowed, please choose a JPEG, PNG, PDF or DOC file.";
}
if ( ! $errors ) {
move_uploaded_file($file_tmp,"uploads/".$file_name);
echo "Success";
}else{
print_r($errors);
}
}
进行array吗？
答案 0 :(得分：0)
这从未得到回答，但我终于得到了答案。
所以这是：
首先 - 我的表格：
log4j.xml然后我的php文件来处理输入：
<form method="post" action="form_action1.php" enctype="multipart/form-data">
<div class="form-group">
<label for="attachment1">Add file</label>
<input type="file" class="form-control-file" id="attachment1" aria-describedby="fileHelp" name="attachment1">
</div>
<div class="form-group">
<button type="submit" class="btn btn-primary" value="submit" name="submit" id="submit">Submit</button>
</div>
</form>
所以我在这里做的是说<?php
$servername = "localhost";
$username = "jobs_usr1";
$password = "XXXXXXX";
try {
$conn = new PDO("mysql:host=$servername;dbname=jobs_users", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
if(isset($_FILES['attachment1'])){
$errors= array();
$file_name = $_FILES['attachment1']['name'];
$file_size = $_FILES['attachment1']['size'];
$file_tmp = $_FILES['attachment1']['tmp_name'];
$file_type = $_FILES['attachment1']['type'];
$file_ext=strtolower(end(explode('.',$_FILES['attachment1']['name'])));
$expensions= array("jpeg","jpg","png","doc","pdf","docx","tif","tiff","zip","xls","xlsx","ppt","pptx","numbers");
if(in_array($file_ext,$expensions)=== false){
$errors[]="extension not allowed, please choose a different file";
}
if ( ! $errors ) {
move_uploaded_file($file_tmp,"uploads/".$file_name);
echo "Success";
echo $file_name;
}else{
print_r($errors);
}
}
$sql = "INSERT INTO `jobs_canjobs`(`attachment1`) VALUES ('$file_name')";
$conn->exec($sql);
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
$conn = null;
?>
意味着输入中有文件，我分配if(isset($_FILES['attachment1'])){，然后我使用$file_name然后将变量放入我的插入声明。
这对我有用。