Question

如何格式化使用time-subtract计算的时差值？考虑这个简单的例子：

(let*
    ((before (current-time))
     (after (progn (sit-for 0.25) (current-time)))
     (diff (time-subtract after before)))
  (insert (format "before: %s--%s\n" before (format-time-string "%Hh%Mm%S.%3Ns" before)))
  (insert (format "after:  %s--%s\n" after (format-time-string "%Hh%Mm%S.%3Ns" after)))
  (insert (format "diff:   %s--%s--%s\n" diff (format-time-string "%s.%3Ns" diff)
                  (format-time-string "%Hh%Mm%S.%3Ns" diff))))

评估它会插入以下内容：

before: (22616 21856 296901 800000)--13h47m12.296s
after:  (22616 21856 552345 800000)--13h47m12.552s
diff:   (0 0 255444 0)--0.255s--16h00m00.255s

两个时间戳之间的差异大约是250毫秒。但是使用格式字符串format-time-string的{{1}}格式化它会产生16。

不应该是0吗？

Answer 1

"16"来自您的时区。

我认为如果您执行(format-time-string "%Hh%Mm%S.%3Ns" diff 0)，您会看到预期的结果（即0）。

格式时间差为％H

1 个答案: