Question

我之前的question最终没有回答我的长期问题，即：

我需要将li:hover ul { display: block; position: absolute; padding:0px; }密码（User_Passwords）与传入的新密码（up_Password）进行比较。如果它们匹配，我需要返回@CurrentPassword，以便代码跟随不同的轨道，而如果它是新密码，则它将1进入表格。这是我认为正在执行的存储过程的一部分：

INSERTed

我已经做了很多测试，我得到的结论是，这总是会返回DECLARE @UserNumberOfPasswords INT DECLARE @ua_pk uniqueidentifier DECLARE @ResetDaysAmount INT DECLARE @AllowedNumberOfPasswords INT DECLARE @CurrentPasswordDate DATE DECLARE @CurrentPassword varchar(25) SELECT * FROM dbo.User_Passwords WHERE ua_fk = @ua_pk ORDER BY up_PasswordDate DESC DELETE FROM User_Passwords WHERE @ua_pk = ua_fk AND @CurrentPasswordDate > (DATEADD(DAY, (@ResetDaysAmount - 1), up_PasswordDate)) SELECT * FROM dbo.User_Passwords WHERE ua_fk = @ua_pk ORDER BY up_PasswordDate ASC SELECT @UserNumberOfPasswords = COUNT(*) FROM User_Passwords AS up WHERE ua_fk = @ua_pk IF @UserNumberOfPasswords > @AllowedNumberOfPasswords BEGIN WITH T AS (SELECT TOP (@UserNumberOfPasswords - @AllowedNumberOfPasswords) * FROM User_Passwords WHERE ua_fk = @ua_pk ORDER BY up_PasswordDate ASC) DELETE FROM T; END IF @UserNumberOfPasswords = @AllowedNumberOfPasswords BEGIN WITH T AS (SELECT TOP 1 * FROM User_Passwords WHERE ua_fk = @ua_pk ORDER BY up_PasswordDate ASC) DELETE FROM T; END IF EXISTS (SELECT 1 FROM User_Passwords WHERE up_Password = @CurrentPassword) SELECT 1 ELSE INSERT INTO User_Passwords (ua_fk, up_Password, up_PasswordDate) VALUES (@ua_pk, @CurrentPassword, @CurrentPasswordDate，我不能完全确定原因。

底线 - 我想比较值，如果值相等，请返回VB.Net并使用一个值，以便我可以将其用于不同的代码路由，而如果它们不相等，我将添加然后返回我的VB.Net代码。

Answer 1

DECLARE @result integer;   

IF EXISTS         (SELECT 1
                   FROM User_Passwords
                   WHERE up_Password = @CurrentPassword)
  BEGIN
    SET @result = 1;
  END;
ELSE
 BEGIN
    INSERT INTO User_Passwords (ua_fk, up_Password, up_PasswordDate)
    VALUES (@ua_pk, @CurrentPassword, @CurrentPasswordDate);
    SET @result = 0;
 END;

RETURN @result;

Answer 2

而不是

IF EXISTS 
    (SELECT 1
    FROM User_Passwords
    WHERE up_Password = @CurrentPassword)
    SELECT 1
ELSE
    INSERT INTO User_Passwords (ua_fk, up_Password, up_PasswordDate)
    VALUES (@ua_pk, @CurrentPassword, @CurrentPasswordDate

不应该

IF EXISTS 
    (SELECT 1
    FROM User_Passwords
    WHERE up_Password = @CurrentPassword
    AND   ua_fk = @ua_pk ) //Only search for passwords that belong to this user
    SELECT 1
ELSE
    INSERT INTO User_Passwords (ua_fk, up_Password, up_PasswordDate)
    VALUES (@ua_pk, @CurrentPassword, @CurrentPasswordDate

...

否则，如果任何用户（不仅仅是感兴趣的用户）存在密码，则存储过程将返回1，这可能会解释您的结果。

Answer 3

如果我需要更多调试

，我通常会添加一个打印件

IF EXISTS 
    (SELECT 1
    FROM User_Passwords
    WHERE up_Password = @CurrentPassword)
    BEGIN
        PRINT ('EXISTS')
        PRINT ('up_Password:' + up_Password)
        PRINT ('@CurrentPassword:' + @CurrentPassword)
    SELECT 1
    END
ELSE
    BEGIN
        PRINT ('NOT EXISTS')
        PRINT ('up_Password:' + up_Password)
        PRINT ('@CurrentPassword:' + @CurrentPassword)
        INSERT INTO User_Passwords (ua_fk, up_Password, up_PasswordDate)
        VALUES (@ua_pk, @CurrentPassword, @CurrentPasswordDate)
    END

如果EXISTS然后ELSE与INSERT，SQL Server

3 个答案: