Question

我的对象看起来像：

object = [[section: "section1", order: "1"],
          [section: "section2", order: "1"],
          [section: "section1", order: "2"],
          [section: "section2", order: "2"]]

我想对它进行排序，结果如下：

[[section: "section1", order: "1"],
 [section: "section1", order: "2"],
 [section: "section2", order: "1"],
 [section: "section2", order: "2"]]

所以我需要按部分排序，并在每个部分按顺序排序。

这就是我正在做的事情：

  return Observable.from(realm
            .objects(Section.self).sorted(byProperty: "order", ascending: true)

字符串“section ..”仅用于示例，它可以是其他东西所以我不能只使用该字符进行排序。我需要X字符串的真正优先级。

Answer 1

要按两个因素对其进行排序，您可以使用＆＃34;排序＆＃34;来自定义逻辑。方法：这是一个你可以在操场上测试的例子。

    struct MyStruct {
    let section: String
    let order: String
}
let array = [MyStruct(section: "section1", order: "1"),
             MyStruct(section: "section2", order: "1"),
             MyStruct(section: "section1", order: "2"),
             MyStruct(section: "section2", order: "2")]

let sortedArray = array.sorted { (struct1, struct2) -> Bool in
    if (struct1.section != struct2.section) { // if it's not the same section sort by section
        return struct1.section < struct2.section
    } else { // if it the same section sort by order.
        return struct1.order < struct2.order
    }
}
print(sortedArray)

Answer 2

let object = [["section": "section1", "order": "2"],
              ["section": "section2", "order": "2"],
              ["section": "section1", "order": "1"],
              ["section": "section2", "order": "1"],
              ["section": "section5", "order": "3"],
              ["section": "section6", "order": "1"],
              ["section": "section5", "order": "1"]]

     let Ordered = object.sorted{$0["order"]! < $1["order"]!  }

    let OrderedObjects = Ordered.sorted{$0["section"]! < $1["section"]!  }


    print(OrderedObjects)

 //[["section": "section1", "order": "1"], ["section": "section1", "order": "2"], ["section": "section2", "order": "1"], ["section": "section2", "order": "2"], ["section": "section5", "order": "1"], ["section": "section5", "order": "3"], ["section": "section6", "order": "1"]]

Answer 3

使用协议

struct A {
    var firstName: String?
    var lastName: String?
}
protocol StringSortable {
    var property1: String {get}
    var property2: String {get}
}
extension A: StringSortable {
    var property1: String {
        return firstName ?? ""
    }
    var property2: String {
        return lastName ?? ""
    }
}
let array1 = [A(firstName: "Dan", lastName: "P2"), A(firstName: "Han", lastName: "P1"), A(firstName: "Dan", lastName: "P0"), A(firstName: "Han", lastName: "P8")]
let sortArray = array1.sorted {
    $0.property1 == $1.property1 ? $0.property2 < $1.property2 : $0.property1 < $1.property1
}
print(sortArray)

Dan P0

Dan P2

Han P1

韩P8

按两个属性排序

3 个答案: