我正在尝试从表中获取记录总数并使用以下MySQL查询:
SELECT COUNT(*) AS cnt FROM `info` WHERE 1 GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d') ORDER BY signup_date DESC
但是导致以下错误:
SQL错误(1055):ORDER BY子句的表达式#1不在GROUP BY子句中,并且包含非聚合列'rentown.info.signup_date' 它在功能上不依赖于GROUP BY子句中的列; 这与sql_mode = only_full_group_by不兼容。[SELECT COUNT() AS cnt FROM
info
WHERE 1 GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d')ORDER BY signup_date DESC]
这是我的表格格式:
+ Options
id email signup_date ip city_name firstname address state lastname city zipcode phonenumber current_url creditscore
4 kfct@yahoo.com 1388525440 108.200.78.136 Philadelphia, PA Kathy 1915 Apex Ave #1/4 California Yeung Los Angeles 90039 310 890 3338 NULL NULL
10 mlh@gmail.com 1388884727 98.199.141.66 Dickinson, TX Mackenzie 102 strand Texas Helms Galveston 77550 409 599 8024 NULL NULL
11 mjma@yahoo.com 1388889053 99.190.210.155 Grand Prairie, TX samathiis 1701 towne crossing blvd #731 Texas ashley mansfield 76063 817 210 NULL NULL
答案 0 :(得分:3)
错误消息非常明显。您只能按GROUP BY
子句中出现的列或聚合排序。要快速修复,只需按分组时使用的相同术语排序。
SELECT COUNT(*) AS cnt
FROM `info`
GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d')
ORDER BY FROM_UNIXTIME(signup_date, '%Y-%m-%d') DESC
答案 1 :(得分:0)
对于总记录数,这应该足够了:
SELECT COUNT (*) AS cnt
FROM 'info'
ORDER BY signup_date DESC