如何将SparseVector转换为MatrixEntry

Question

这是我的SparseVector：

mx.foreach(println)

SparseVector((0,1.0), (1,0.0), (2,0.0), (3,0.0), (4,0.0), (5,0.0), (6,0.0), (7,0.0), (8,0.0), (9,0.0), (10,0.0), (11,0.0), (12,0.0))
SparseVector((0,0.0), (1,1.0), (2,0.0), (3,0.0), (4,0.0), (5,0.0), (6,0.0), (7,0.0), (8,0.0), (9,0.0), (10,0.0), (11,0.0), (12,0.0))
SparseVector((0,0.0), (1,0.0), (2,1.0), (3,0.0), (4,0.0), (5,0.0), (6,0.0), (7,0.0), (8,0.0), (9,0.0), (10,0.0), (11,0.0), (12,0.0))
SparseVector((0,0.0), (1,0.0), (2,0.0), (3,1.0), (4,0.0), (5,0.0), (6,0.0), (7,0.0), (8,0.0), (9,0.0), (10,0.0), (11,0.0), (12,0.0))

我想转换为MatrixEntry？

Answer 1

编辑：鉴于mx的类型为RDD[SparseVector[Double]]：

val matrixEntries: RDD[MatrixEntry] = mx.zipWithIndex.flatMap {
  case (vector, i) => vector.toArray.zipWithIndex.map {
    case (v, j) => MatrixEntry(i, j, v)
  }
}