两个表之间的交叉间隔日期

Question

您好我需要将两个具有间隔日期的表交叉

时间表1

start               | end
---------------------------------------------
2016-12-19 08:00:00 | 2016-12-19 08:30:00
2016-12-19 09:30:00 | 2016-12-19 11:00:00

时间表2

start               | end
---------------------------------------------
2016-12-19 08:30:00 | 2016-12-19 10:00:00
2016-12-19 10:30:00 | 2016-12-19 11:00:00

这是我试过的SQL：

SELECT * FROM start, end FROM timeline1 
INTERSECT
SELECT * FROM start, end FROM timeline2 

需要这样的结果：

总计：00：60：00

Answer 1

使用range operators * and &&：

select tsrange(t1."start", t1."end") * tsrange(t2."start", t2."end") as "intersections"
from timeline1 t1
join timeline2 t2 
on tsrange(t1."start", t1."end") && tsrange(t2."start", t2."end");

                 intersections                  
-----------------------------------------------
 ["2016-12-19 09:30:00","2016-12-19 10:00:00")
 ["2016-12-19 10:30:00","2016-12-19 11:00:00")
(2 rows)    

间隔总和：

select sum(upper("intersections")- lower("intersections")) as total
from (
    select tsrange(t1."start", t1."end") * tsrange(t2."start", t2."end") as "intersections"
    from timeline1 t1
    join timeline2 t2 
    on tsrange(t1."start", t1."end") && tsrange(t2."start", t2."end")
) s

  total   
----------
 01:00:00
(1 row)