AJAX - 尝试使用去抖动实现实时搜索

时间:2016-12-19 10:13:18

标签: javascript php jquery ajax underscore.js

我尝试用AJAX实现AJAX实时搜索,我做得很好。然后我尝试添加_.debounce函数,这样它就不会使服务器超载但是效果不好..

这是代码:

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>PHP Live MySQL Database Search</title>
    <script src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function(){
            $('.search-box input[type="text"]').on("keyup input", _.debounce(function(){
                /* Get input value on change */
                var term = $(this).val();
                var resultDropdown = $(this).siblings(".result");
                if(term.length){
                    $.get("backend-search.php", {query: term}).done(function(data){
                        // Display the returned data in browser
                        resultDropdown.html(data);
                    });
                } else{
                    resultDropdown.empty();
                }
            }),250);

            // Set search input value on click of result item
            $(document).on("click", ".result p", function(){
                $(this).parents(".search-box").find('input[type="text"]').val($(this).text());
                $(this).parent(".result").empty();
            });
        });
    </script>
</head>
<body>
<div class="search-box">
    <input type="text" autocomplete="off" placeholder="Search country..." />
    <div class="result"></div>
</div>
</body>
</html>

这是php文件:

<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "root", "", "demo");

// Check connection
if($link === false){
    die("ERROR: Could not connect. " . mysqli_connect_error());
}

// Escape user inputs for security
$query = mysqli_real_escape_string($link, $_REQUEST['query']);

if(isset($query)){
    // Attempt select query execution
    $sql = "SELECT * FROM countries WHERE name LIKE '" . $query . "%'";
    if($result = mysqli_query($link, $sql)){
        if(mysqli_num_rows($result) > 0){
            while($row = mysqli_fetch_array($result)){
                echo "<p>" . $row['name'] . "</p>";
            }
            // Close result set
            mysqli_free_result($result);
        } else{
            echo "<p>No matches found for <b>$query</b></p>";
        }
    } else{
        echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
    }
}

// close connection
mysqli_close($link);
?>

谢谢!

2 个答案:

答案 0 :(得分:1)

您的代码不包含Underscore库,因此_.debounce()无法使用。也就是说,通过setTimeout()调用,您可以轻松实现该方法的功能:

var timeout;
$('.search-box input[type="text"]').on("keyup input", function() {
    var term = $(this).val();
    var $resultDropdown = $(this).siblings(".result");

    clearTimeout(timeout);
    timeout = setTimeout(function() {
        if (term.trim().length) {
            $.get("backend-search.php", { query: term }).done(function(data) {
                $resultDropdown.html(data);
            });
        } else {
            $resultDropdown.empty();
        }
    }, 250);
});

答案 1 :(得分:1)

您可以通过设置 setTimeout 来实现此目的,以便在经过特定时间后对输入上发生的每个更改进行 ajax 调用,但不要忘记终止之前的调用。您可以使用下面的代码来声明任何功能。

var debounce;
$('#input').on('input', function (e) {
    clearTimeout(debounce);
    debounce = setTimeout( 
      function () { 
        searchText(e.target.value) 
      }, 1000
    );
});