我希望EntityType
选择multiple
,因为Sonata会对sonata_type_model
(ModelType
)进行选择。
问题是,如何在我的自定义表单上sonata_type_model
之外使用SonataAdminBundle
?
我试过了:
->add('countries', 'sonata_type_model', array(
'label' => 'Countries',
'property' => 'name',
'multiple' => true
))
我也试过了:
use Sonata\AdminBundle\Form\Type\ModelType;
...
->add('countries', ModelType::class, array(
'label' => 'Countries',
'property' => 'name',
'multiple' => true
))
但不幸的是我收到了一个错误:
捕获致命错误:参数1传递给 索纳塔\ AdminBundle \表格\选择列表\ ModelChoiceLoader :: __结构() 必须实现接口 Sonata \ AdminBundle \ Model \ ModelManagerInterface,null给定,调用 C:\ XAMPP \ htdocs中\ trainingexperience_symfony \程序\缓存\ dev的\ classes.php 在18005行并定义
更新
我遵循建议在表单类型选项中定义model_manager
属性:
protected $modelManager;
function __construct(ModelManager $modelManager)
{
$this->modelManager = $modelManager;
}
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('preferredCountries', ModelType::class, array(
'label' => 'Countries',
'property' => 'name',
'multiple' => true,
'model_manager' => $this->modelManager
));
...
}
我从控制器传递它,如:
/** @var ModelManager $modelManager */
$modelManager = $this->get('sonata.media.admin.media.manager');
$formType = new FormType($modelManager);
...
但现在我收到了一个错误:
班级不存在
500内部服务器错误 - ReflectionException
堆栈跟踪
in vendor\doctrine\common\lib\Doctrine\Common\Persistence\AbstractManagerRegistry.php at line 197 -
$class = $this->getAliasNamespace($namespaceAlias) . '\\' . $simpleClassName;
}
$proxyClass = new \ReflectionClass($class);
if ($proxyClass->implementsInterface($this->proxyInterfaceName)) {
if (! $parentClass = $proxyClass->getParentClass()) {
at ReflectionClass ->__construct ('')
in vendor\doctrine\common\lib\Doctrine\Common\Persistence\AbstractManagerRegistry.php at line 197 +
at AbstractManagerRegistry ->getManagerForClass (null)
in vendor\sonata-project\doctrine-orm-admin-bundle\Model\ModelManager.php at line 272 +
at ModelManager ->getEntityManager (null)
in vendor\sonata-project\doctrine-orm-admin-bundle\Model\ModelManager.php at line 64 +
at ModelManager ->getMetadata (null)
in vendor\sonata-project\doctrine-orm-admin-bundle\Model\ModelManager.php at line 377 +
at ModelManager ->getIdentifierFieldNames (null)
in vendor\sonata-project\admin-bundle\Form\ChoiceList\ModelChoiceLoader.php at line 75 +
at ModelChoiceLoader ->__construct (object(ModelManager), null, 'name', null, array(), object(PropertyAccessor))
in vendor\sonata-project\admin-bundle\Form\Type\ModelType.php at line 113 +
at ModelType ->Sonata\AdminBundle\Form\Type\{closure} (object(OptionsResolver), null)
in vendor\symfony\symfony\src\Symfony\Component\OptionsResolver\OptionsResolver.php at line 859 +
at OptionsResolver ->offsetGet ('choice_loader')
in vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\Type\ChoiceType.php at line 320 +
at ChoiceType ->Symfony\Component\Form\Extension\Core\Type\{closure} (object(OptionsResolver), null)
in vendor\symfony\symfony\src\Symfony\Component\OptionsResolver\OptionsResolver.php at line 965 +
at OptionsResolver ->offsetGet ('choice_list')
in vendor\symfony\symfony\src\Symfony\Component\OptionsResolver\OptionsResolver.php at line 791 +
at OptionsResolver ->resolve (array('label' => 'Countries', 'property' => 'name', 'multiple' => true, 'model_manager' => object(ModelManager)))
in vendor\symfony\symfony\src\Symfony\Component\Form\ResolvedFormType.php at line 156 +
at ResolvedFormType ->createBuilder (object(FormFactory), 'preferredCountries', array('label' => 'Countries', 'property' => 'name', 'multiple' => true, 'model_manager' => object(ModelManager)))
in vendor\symfony\symfony\src\Symfony\Component\Form\Extension\DataCollector\Proxy\ResolvedTypeDataCollectorProxy.php at line 89 +
at ResolvedTypeDataCollectorProxy ->createBuilder (object(FormFactory), 'preferredCountries', array('label' => 'Countries', 'property' => 'name', 'multiple' => true, 'model_manager' => object(ModelManager)))
in vendor\symfony\symfony\src\Symfony\Component\Form\FormFactory.php at line 114 +
at FormFactory ->createNamedBuilder ('preferredCountries', 'Sonata\AdminBundle\Form\Type\ModelType', null, array('label' => 'Countries', 'property' => 'name', 'multiple' => true, 'model_manager' => object(ModelManager)))
in vendor\symfony\symfony\src\Symfony\Component\Form\FormBuilder.php at line 106 +
at FormBuilder ->create ('preferredCountries', 'Sonata\AdminBundle\Form\Type\ModelType', array('label' => 'Countries', 'property' => 'name', 'multiple' => true, 'model_manager' => object(ModelManager)))
in vendor\symfony\symfony\src\Symfony\Component\Form\FormBuilder.php at line 269 +
at FormBuilder ->resolveChildren ()
in vendor\symfony\symfony\src\Symfony\Component\Form\FormBuilder.php at line 215 +
at FormBuilder ->getForm ()
in vendor\symfony\symfony\src\Symfony\Component\Form\FormFactory.php at line 40 +
at FormFactory ->create (object(InternshipType), object(Internship), array())
in vendor\symfony\symfony\src\Symfony\Bundle\FrameworkBundle\Controller\Controller.php at line 282 +
at Controller ->createForm (object(InternshipType), object(Internship))
in src\IndexBundle\Controller\TraineeController.php at line 194 +
at TraineeController ->internshipsAction (object(Request))
at call_user_func_array (array(object(TraineeController), 'internshipsAction'), array(object(Request)))
in vendor\symfony\symfony\src\Symfony\Component\HttpKernel\HttpKernel.php at line 144 +
at HttpKernel ->handleRaw (object(Request), '1')
in vendor\symfony\symfony\src\Symfony\Component\HttpKernel\HttpKernel.php at line 64 +
at HttpKernel ->handle (object(Request), '1', true)
in vendor\symfony\symfony\src\Symfony\Component\HttpKernel\DependencyInjection\ContainerAwareHttpKernel.php at line 69 +
at ContainerAwareHttpKernel ->handle (object(Request), '1', true)
in vendor\symfony\symfony\src\Symfony\Component\HttpKernel\Kernel.php at line 185 +
at Kernel ->handle (object(Request))
in web\app_dev.php at line 30 +
答案 0 :(得分:0)
您应该尝试为该类型提供model_manager
选项。它可能是一项服务,因此请查看debug:container
并尝试发现它。
答案 1 :(得分:0)
您收到此错误是因为sonata_type_model需要目标管理员的模型管理员来操纵实体。
结论:你不能在没有定义管理服务的实体上使用sonata_type_model
以下是我使用的解决方法:
表格类型:
pymysql
}
如您所见,我正在定义选项并查看sonata_type_model需要的变量,现在是表单类型的模板
<?php
namespace Blast\BaseEntitiesBundle\Form\Type;
use Symfony\Component\Form\FormInterface;
use Symfony\Component\Form\FormView;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\OptionsResolver\Options;
use Blast\CoreBundle\Form\AbstractType;
class NestedTreeableType extends AbstractType
{
public function configureOptions(OptionsResolver $resolver)
{
$queryBuilder = function (Options $options)
{
return $options['em']
->getRepository($options['class'])
->getNodesHierarchyQueryBuilder();
};
$choiceLabel = function($choice)
{
return str_repeat(' - ', $choice->getTreeLvl()) . (string) $choice;
};
$resolver->setDefaults([
'query_builder' => $queryBuilder,
'choice_label' => $choiceLabel,
'btn_add' => 'link_add',
'btn_list' => 'link_list',
'btn_delete' => 'link_delete',
'btn_catalogue' => 'SonataAdminBundle',
]);
}
public function buildView(FormView $view, FormInterface $form, array $options)
{
parent::buildView($view, $form, $options);
$object_id = ($view->vars['name'] == 'treeParent') ? $form->getParent()->getData()->getId() : null;
$choices = [];
foreach ($view->vars['choices'] as $choice) {
if ( $object_id && $choice->data->getId() == $object_id )
$choice->attr['disabled'] = 'disabled';
$choices[] = $choice;
}
$view->vars['choices'] = $choices;
$view->vars['btn_add'] = $options['btn_add'];
$view->vars['btn_list'] = $options['btn_list'];
$view->vars['btn_delete'] = $options['btn_delete'];
$view->vars['btn_catalogue'] = $options['btn_catalogue'];
}
public function getParent()
{
return 'entity';
}
public function getBlockPrefix()
{
return 'blast_nested_treeable';
}
只需渲染一个sonata_type_model块就可以了。 如果你想看看真实的例子:https://github.com/blast-project/BaseEntitiesBundle
希望有所帮助
答案 2 :(得分:0)
我不知道有人还在搜索那个,但是,我发现你需要这个才能拥有modelManager(至少在2.7版本的symfony中):
/** @var ModelManager $modelManager */
$modelManager = $this->get('sonata.admin.manager.orm');
$formType = new FormType($modelManager);
...
byez