Question

我正在尝试使用以下函数将数据保存到sqlite数据库中。

func insertSpecieDetail(_ specieId: Int)
{
    //
    //  Create a temporary SpecieDetailModel for storing our values from the query.
    //
    let specieDetail: SpecieDetailModel = SpecieDetailModel()

    //
    //  Create an instance of our statement for SQLite to use.
    //
    var statement: OpaquePointer? = nil


    let update:String = String(format:SQL.InsertUserUpdates, specieId)
    if sqlite3_prepare_v2(self.database, update, -1, &statement, nil) == SQLITE_OK {

        sqlite3_bind_text(statement, 1, specieDetail.userCommonName, -1, nil);
        sqlite3_bind_text(statement, 2, specieDetail.userCommonNameFR, -1, nil);
        sqlite3_bind_text(statement, 3, specieDetail.userCommonNameES, -1, nil);
        sqlite3_bind_text(statement, 4, specieDetail.userCommonNameDE, -1, nil);
        sqlite3_bind_text(statement, 5, specieDetail.userNotes, -1, nil);

        if sqlite3_step(statement) == SQLITE_DONE {
            print("Successfully inserted row.")
        } else {
            print("Could not Update row.")
        }
    }

        sqlite3_finalize(statement)
}

SQL.InsertUserUpdates =

"INSERT INTO RL_Species (user_common_name, user_common_name_fr, user_common_name_es, user_common_name_de, user_notes) VALUE (?, ?, ?, ?, ?)" + "WHERE RL_Species.id = %d"

没有收到任何错误，但系统在命令后跳过：

if sqlite3_prepare_v2(self.database, update, -1, &statement, nil) == SQLITE_OK

在同一行，我检查了什么＆＃34;更新＆＃34;等于并低于

"INSERT INTO RL_Species (user_common_name, user_common_name_fr, user_common_name_es, user_common_name_de, user_notes) VALUE (?, ?, ?, ?, ?)WHERE RL_Species.id = 8"

所以看起来该字符串正在找到specieId OK。

我错过了什么？

更新：找到VALUE vs. VALUES错误，但仍然出现错误＆＃34;在＆＃34;附近WHERE

func insertSpecieDetail(_ specieId: Int)
{
    //
    //  Create a temporary SpecieDetailModel for storing our values from the query.
    //
    let specieDetail: SpecieDetailModel = SpecieDetailModel()

    //
    //  Create an instance of our statement for SQLite to use.
    //
    var statement: OpaquePointer? = nil

    let update = "INSERT INTO RL_Species (user_common_name, user_common_name_fr, user_common_name_es, user_common_name_de, user_notes) VALUES ('\(specieDetail.commonName)', '\(specieDetail.commonNameFR)', '\(specieDetail.commonNameES)', '\(specieDetail.commonNameDE)', '\(specieDetail.userNotes)') WHERE RL_Species.id = '\(specieId)';"

    if sqlite3_prepare_v2(database, update, -1, &statement, nil) == SQLITE_OK {


        if sqlite3_step(statement) == SQLITE_DONE {
            print("Successfully inserted row.")
        } else {
            print("Could not Update row.")
        }
    } else {

        // forces SQLite to send error message
        let errorMessage = String.init(validatingUTF8: sqlite3_errmsg(database))!
        print("update failed! \(errorMessage)")        }

        sqlite3_finalize(statement)
}

使用Swift 3插入SQLite数据库

0 个答案: